### Author Topic: *v^2 in a physlets formula for air resistance  (Read 13525 times)

#### Fu-Kwun Hwang

• Hero Member
• Posts: 3062
##### Re: *v^2 in a physlets formula for air resistance
« Reply #15 on: June 15, 2010, 10:39:56 am »
When the initlal velocity of the projectile is in the horizontal:
Then it will move with constant speed in the horizontal direction and it will also have free fall motion in the vertical direction.

Why it should only move horizontally? or even not moving???

#### ahmedelshfie

• Hero Member
• Posts: 930
##### Re: *v^2 in a physlets formula for air resistance
« Reply #16 on: June 15, 2010, 06:26:08 pm »
I thought when i drag theta to 0.0 and initial V to 0.0
So we no have velocity or angle,so no have movement.
I mean when it should move horizontally this if we drag only initial V without drag theta,
So we will have velocity without angle in this case i think move horizontally.
However prof thanks i understand your explain now I'm just try understand every thing about simulation
« Last Edit: June 15, 2010, 07:25:33 pm by ahmedelshfie »

#### Fu-Kwun Hwang

• Hero Member
• Posts: 3062
##### Re: *v^2 in a physlets formula for air resistance
« Reply #17 on: June 16, 2010, 07:33:18 pm »
You did not add any action when initial velocity slider were changed.
I add _initialize() to the action. And it should work fine when you drag slider for V.

#### ahmedelshfie

• Hero Member
• Posts: 930
##### Re: *v^2 in a physlets formula for air resistance
« Reply #18 on: June 16, 2010, 07:46:35 pm »
Thanks prof i fix wrong and now work very well without any wrong
Thanks
Now simulation on Airdrag
« Last Edit: June 16, 2010, 09:27:07 pm by ahmedelshfie »

#### panya.p

• Newbie
• Posts: -6
##### Re: *v^2 in a physlets formula for air resistance
« Reply #19 on: January 22, 2020, 03:12:01 pm »