Author Topic: Electron in magnetic field  (Read 55228 times)

Fu-Kwun Hwang

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Electron in magnetic field
« on: May 16, 2005, 04:09:01 pm »
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It is assumed there are uniform magnetic field in the simulation region except white background area (there is no magnetic field).
An electron enter magnetic field is not trapped in the magnetic field. It will come out the region eventually.

You can change charge/ mass /magnetic field and the width of the white region with sliders. Enjoy it!



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d211275

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Re: Electron in magnetic field
« Reply #1 on: May 09, 2007, 10:51:15 am »
Thanks alot.It's very useful for me.

Fu-Kwun Hwang

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Re: Electron in magnetic field
« Reply #2 on: May 19, 2007, 12:51:40 am »
You are welcomed!

Gizmo0105

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Re: Electron in magnetic field
« Reply #3 on: September 26, 2007, 05:39:22 pm »
Hi, thanks a lot for the simulation its very helpful.

Im currently doing an investigation for school on electrons in magentic and electrostatic fields. However I cannot perform the most common investigation (Charge to mass ratio) as this is already in the course.
Any suggestions would be greatly appreciated

Fu-Kwun Hwang

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Re: Electron in magnetic field
« Reply #4 on: September 27, 2007, 01:51:09 am »
For electron with charge q move in E and B field.
The force will be q (E+vXB)
If the acceleration is a, and mass is m, then

ma= q (E+vXB) ;
so a=(q/m) (E+vXB)

If you can measure acceleration(in any way). You will know the q/m ratio.

Ganeshchandra

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Re: Electron in magnetic field
« Reply #5 on: October 29, 2007, 07:33:22 pm »
thanks

basit_fastian

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Re: Electron in magnetic field
« Reply #6 on: November 16, 2007, 12:41:47 pm »
hi
thanks for this beautiful site and knowledge of physics keeping on the java aplet and this aplet give me a lot of knowledge to me about eletron in magnetic field.

Alfcon

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Re: Electron in magnetic field
« Reply #7 on: September 11, 2009, 07:51:26 am »
I am new to all this and have just started to teach my self some of the basic aspects of Electrons and magnetic fields.  I have looked at your java program in the Topic: Electron in magnetic field, and I have a few questions.

Q = charge
m = mass
d = Magnetic field
b = ?

What does b represent ?

Fu-Kwun Hwang

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Re: Electron in magnetic field
« Reply #8 on: September 11, 2009, 09:32:26 am »
B stands for magnetic field : there is a uniform magnetic field in most of the simulation region except region with white background.
d: is the width of the white back ground region where there is no magnetic field (B=0).

Try to change slider value and watch what is changed in the simulation.

Alfcon

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Re: Electron in magnetic field
« Reply #9 on: September 11, 2009, 11:33:49 am »
ok got it now, one more question. 

If b is the magnetic field and i can be set from 1 to 10.

Is b set to 1 =  1 Tesla, b set to 10 = 10 Tesla?


Fu-Kwun Hwang

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Re: Electron in magnetic field
« Reply #10 on: September 11, 2009, 03:40:41 pm »
This is a good question. Because you might reach a wrong interpreatation if you was not careful when chose unit for the ststem.

$vec{F}=q vec{v}   imes vec{B}$ is used to calculate the motion in the simulation.
For a simulation, the same length in the simulation can be 1cm or 1m or 1km.
It depends on how you interprete the system.

In the above system, you can select the unit of B as Tesla, then the unit in space (x,y coordinate) will be meter, charge will be Coulomb. Unit for velocity will be m/s.

If you want to interprete it as a real electron:
qe=1.6 10-19 C, me=9.1 10-31kg.
m_e/q_e=5.69 10-12 kg/C,

If you want to interprete B as Tesla, then the unit of 1 second in the simulation represent 5.69 10-12s in real case. It means that the electron will move very fast. However, it can not be faster then speed of light c=3 108m/s (less than 0.01c will be fine to ignore relativistic effect), so the unit of length can not be meter(m). However, $mu$m (10-6m) can be used.

If the unit of B is selected as gauss (1 gauss=10-4 Tesla), then unit of length can be selected as mm (10-3m).