NTNUJAVA Virtual Physics Laboratory
Easy Java Simulations (2001 ) => Collaborative Community of EJS => Topic started by: lookang on August 29, 2012, 05:23:11 pm

Ejs Open Source Heat capacity and Specific heat capacity Java Applet by lookang, customized based on an earlier model http://www.compadre.org/osp/items/detail.cfm?ID=10071 by Wolfgang Christian.
Aims
1. To investigate the relationship between the heat capacity of an object and the heat transferred per unit temperature change of the object.
2. To infer the specific heat capacity of a substance from the heat capacity of an object of the same substance.
Syllabus Learning Outcome
This lesson exemplar addresses the following learning outcome:
 define the terms heat capacity and specific heat capacity
 recall and apply the relationship
Thermal energy = mass X specific heat capacity X change in temperature
Assumption in the model
heat lost by the solid cylinder to the water is completely gain by the water, in other words, the container containing the water and solid cylinder is a perfect insulator.
Definition Equation 1
The heat capacity, C, of a body is defined as the amount of heat (or thermal energy) required to raise the temperature of a body by 1 oC (or 1 K).
therefore, heat capacity, C (units: J oC1) = heat transferred (in J) / temperature change (in oC)
Definition Equation 2
The specific heat capacity, c, of a substance is defined as the amount of heat (or thermal energy) required to raise the temperature of a unit mass of the substance by 1 oC (or 1 K).
therefore specific heat capacity, c (in J oC1kg1 ) = heat transferred (in J) / temperature change (in oC) x mass of object (in kg)

changes made:
design the water properties and rate of heat flow to depend on water instead of the older surrounding
made water mass and initial temperature variables
added hints and answers Qsolid and Qwater, notice Qsolid + Qwater = 0, assuming no heat Q loss to surrounding
data here https://docs.google.com/spreadsheet/ccc?key=0AjIvSgTzZrZdFpVOXRTMlZrb2J1UEd5VThxZlJrQlE
m C Ti Tf Q = mc(tfTi) TfTi
0.1 385 20 52.6 1,255 32.6
0.1 385 20 61.9 1,613 41.9
0.1 385 20 71.2 1,971 51.2
0.1 385 20 80.6 2,333 60.6
0.1 385 20 89.9 2,691 69.9
work in progress
enjoy!