- #1

- 15

- 0

k is a constant

solving this ODE, r = +/- sqrt(-k)

if k > 0, then r = +/- sqrt(k)i

so G is in the form Acos(sqrt(k)x) + Bsin(sqrt(k)x)

so, what if k is a complex number, then

r = +/- sqrt(-ki)

then what is the form of G?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter madeinmsia
- Start date

- #1

- 15

- 0

k is a constant

solving this ODE, r = +/- sqrt(-k)

if k > 0, then r = +/- sqrt(k)i

so G is in the form Acos(sqrt(k)x) + Bsin(sqrt(k)x)

so, what if k is a complex number, then

r = +/- sqrt(-ki)

then what is the form of G?

- #2

- 218

- 0

so, what if k is a complex number, then

r = +/- sqrt(-ki)

then what is the form of G?

Don't you know how to calculate the square root of a complex number?

Share: