The power loss due to current I(t)=A\, \sin\omega t for resistor R is
P=I^2R=A^2\, \sin^2\omega t \, R=A^2 \frac{1-\cos 2\omega t}{2} \, R

The following applet draw 3 curves
1.  A\, \sin\omega t

2. A^2\, \sin^2\omega t

3. B -\frac{A^2\cos 2\omega t}{2} where B can be adjust by right slider from 0 to \frac{A^2}{2}


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