The power loss due to current $I(t)=A\, \sin\omega t$ for resistor R is
$P=I^2R=A^2\, \sin^2\omega t \, R=A^2 \frac{1-\cos 2\omega t}{2} \, R$

The following applet draw 3 curves
1.  $A\, \sin\omega t$

2. $A^2\, \sin^2\omega t$

3. $B -\frac{A^2\cos 2\omega t}{2}$ where $B$ can be adjust by right slider from 0 to $\frac{A^2}{2}$

/htdocs/ntnujava/ejsuser/2/users/ntnu/fkh/sin2_pkg/sin2.propertiesFull screen applet or Problem viewing java?Add http://www.phy.ntnu.edu.tw/ to exception site list