The final \omega I get is 1.98057060132 (i.e. when \theta = 0 )
so when we're bottom of the pendulum (or the end of the slope)

\vec{N} = - (mr\omega^2+mg\cos\theta) \hat{r}
since \theta = 0 shouldn't
mr\omega^2 = mg?
because mine comes out as
mr\omega^2 = 2mg?