The final $\omega$ I get is 1.98057060132 (i.e. when $\theta = 0$ )
so when we're bottom of the pendulum (or the end of the slope)

$\vec{N} = - (mr\omega^2+mg\cos\theta) \hat{r}$
since $\theta = 0$ shouldn't
$mr\omega^2 = mg$?
because mine comes out as
$mr\omega^2 = 2mg$?