But Ohm's law states that V = IR.

So if I were to substitute this into the Ploss equation above, I end up with [b]Ploss = V^2/R[/b]. Which means if the voltage is higher, the Ploss would be higher.

Do these seem conflicting?

I appreciate your help to reconcile this.

Thanks in advance for your assistance.

Lim Heng Leng