And there is a gravitation field between particles

where is the unit vector between those two particles.

What is the minimum initial velocity for particle a to circular the orbit?

Because the field is so the potential energy is

From consevation of energy

So the minimum velocity is

What if we want the particle always touch the inner surface at r=a (i.e. the Normal force provided by the circular orbit is always pointing into the center of the circle)

Do you know how to solve it?

The following is the simulation for you to play with.

You can drag particle B ( to change b)

Mode:

1. [b]N out[/b] the normal force is always pointing away from the center of the circle and v is the minimum velocity to reach another end.

2. [b]N in[/b]the normal force is always pointing into the center of the circle and v is the minimum velocity

3. You can change cst to change the velocity ratio.

The red arrow is the velocity of the particle a (You can drag the arrow to change velocity)

The blue arrow is the gravitation force between particle A and B.

The magenta arrow is the required Centripetal force.

Another black arrow is the normal force supplied by the circular orbit.

The kinetic energy/potential energy and total energy as function of angle are drawn as red/blue and green curves.

/htdocs/ntnujava/ejsuser/2/users/ntnu/fkh/circularorbitNgravity_pkg/circularorbitNgravity.propertiesFull screen applet or Problem viewing java?Add http://www.phy.ntnu.edu.tw/ to exception site list

Download EJS jar file(1356.1kB):double click downloaded file to run it. (12 times by 7 users) , Download EJS source (6 times by 4 users) View EJS source