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answer is (C) [color=red]Vx[/color]=?2[color=blue] Vx[/color], [color=red]Vy[/color]= ?2 [color=blue]Vy[/color]

by solving by differentiation

since y1 = 4.t - 2.t^2
dy1/dt = 4 - 4.t

y2 = Math.sqrt(2).4.t - 2.t^2
dy2/dt = Math.sqrt(2).4 - 4.t

realizing when t = 0 gives the same answer as t = end point for vy1 and vy2

vy1 = dy1/dt = 4 - 4.t = 4 - 4.0 = 4
vy2 = dy2/dt = Math.sqrt(2).4 - 4.t =Math.sqrt(2).4 - 4.t = Math.sqrt(2).4 .

therefore vy2 = Math.sqrt(2).vy1


similarly,

x1 = t
vx1 = dx1/dt = 1 = vx1 (constant so at end point is the same)

x2 = Math.sqrt(2).t
vx2 = dx2/dt = Math.sqrt(2)

vx2 = Math.sqrt(2).vx1