Dear Prof Hwang your reply 1 and my reply 1. Thank you for the reply and the link to the applet. They are very illuminating. The point where I find difficulty in my understanding and where I need to explain to the students is how does the potential of the capacitor attain the same voltage (i.e V) in the circuit that I had described in my question. The plate connected to the capacitor may attain V volts since it is connected directly to the battery positive thro' switch at the immediate instance when the switch is closed. But what about the other plate i.e terminal A of the resistor since there is no apparent connection to the battery and since the resistor and the negative terminal of the battery is coming in between. For this I need to blend probably electrostatics and electric circuit behaviour it seems. They have and including me have background about Physics by Resnick and Halliday about potential and electric fields but the fine links needed to explain the phenomenon is not explained clearly in Resnick text book also. Thanks Sridhar