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 1 work « Embed this message on: February 06, 2004, 03:29:00 am »

A rectangulat tank that is three feet long and two feet wide and two feet deep contains water that is 1.5 feet in depth calculate the amount of work required to pump half of the water over the top of the tank (weight density of water is 62.5 pounds per cubic foot)?
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Fu-Kwun Hwang
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 « Embed this message Reply #1 on: February 06, 2004, 04:41:26 pm » posted from:Taipei,T'ai-pei,Taiwan

Use conservation of energy:
Calculate the total potential energy (related to water surface) for upper half of water !
$U= \int dm \cdot g \cdot y =\int \rho \cdot dV \cdot g \cdot y =\int \rho \cdot A \cdot dy \cdot g \cdot y$
where $\rho$ is the density, A is the area
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 « Embed this message Reply #2 on: June 29, 2007, 01:39:38 pm »

A little bit of confused... What is that?
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To live close to great minds is the best kind of education. ..."John Buchan (1875~1940 Scotticsh historian, Governor General of Canada)"