NTNUJAVA Virtual Physics Laboratory
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Author Topic: Free Fall modelling with Friction force F = k*v  (Read 8797 times)
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lookang
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on: November 26, 2008, 01:13:20 pm » posted from:SINGAPORE,SINGAPORE,SINGAPORE

Free Fall Modeling Activities
Install Ejs and then right-click on a launch node (green arrow) to copy the Free Fall model from this jar file into the Ejs workspace to do the following activities.
Friction
The Free Fall model assumes that energy is lost only during the floor collision. Set the coefficient of restitution to 1.0 in the model and modify the differential equation to include energy loss due to friction (fluid drag). This energy loss can be modeled by including a friction force Ffriction that is proportional to the velocity:
Ffriction= - b v .
The drag coefficient b depends on the shape of the object and should be included in the model as an additional variable. A good value for simulation is b/m =0.1 although realistic values for objects in air is lower. What is the significance of the negative sign in the friction formula?

My input/contributions are
1. variable k
2. variable mass

3. ODE becomes dvy/dt = -g - k/mass*(vy)



source code
download the *.jar for using the applet on standalone without internet connection.

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Press the Alt key and the left mouse button to drag the applet off the browser and onto the desktop. This work is licensed under a Creative Commons Attribution 2.5 Taiwan License
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* freefall01.PNG (23 KB, 1023x735 - viewed 248 times.)
« Last Edit: August 03, 2009, 02:23:21 pm by lookang » Logged
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