Magnetic field generated bar magnet

Fu-Kwun Hwang

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1 Magnetic field generated bar magnet

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on: August 13, 2008, 08:43:04 am »

Registed user can get files related to this applet for offline access.
Problem viewing java?Add http://www.phy.ntnu.edu.tw/ to exception site list
If java program did not show up, please download and install latest Java RUN TIME

You can drag the magnetic neddle to generate another sets of magnetic field line when the simulation is in pause state (when it finish generate the field line or click pause button).


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lookang

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2 Re: Magnetic field generated bar magnet

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Reply #1 on: August 13, 2008, 06:07:21 pm »

my journey:

1. added mbar.gif graphics into folder _data/mbar.gif
so now i can compile it n it works nicely.

question:

reference:http://upload.wikimedia.org/math/5/f/f/5ff6494ee391f0ac7cfd0da8851422f3.png
can explain is this the Biot–Savart law you used to model the magnetic feild lines?

compare it with the code

Code:

double r2,r3,f;
// caluclate magnetic field at point xp,yp use Biot-Savart Law Fproportional to dlXr/r^3
public double calFx (double xp,double yp) {
f=0;
for(int i=0;i for(int j=0;j r2=(xp-xc[j])*(xp-xc[j])+(yp-yc[i])*(yp-yc[i])+zc[i]*zc[i];
r3=r2*Math.sqrt(r2);
f-=(yc[i]*(yp-yc[i])-zc[i]*zc[i])/r3;
}
}
return f;
}
public double calFy (double xp,double yp) {
f=0;
for(int i=0;i for(int j=0;j r2=(xp-xc[j])*(xp-xc[j])+(yp-yc[i])*(yp-yc[i])+zc[i]*zc[i];
r3=r2*Math.sqrt(r2);
f+=yc[i]*(xp-xc[j])/r3;
}
}
return f;
}

it looks different, sorry it is difficult to follow, as Biot-Savart Law i don't have a deep understanding

i am usuallly on MSN microsoft messager : lookang , can add me as frd then maybe we can arrange to discuss the applet?


« Last Edit: August 13, 2008, 06:11:25 pm by lookang »	Logged

Fu-Kwun Hwang

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3 Re: Magnetic field generated bar magnet

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Reply #2 on: August 14, 2008, 11:53:27 pm »

Original form for Biot-Savart Law is
$d\vec{B}=\frac{\mu_0}{4\pi} \frac{I\,d\vec{l}\times\hat{r}} {r^2}$

For the calculation in the code. I use another variable(cst) to represent $\frac{\mu_o\, I}{4\pi}$
And transform $\frac{I\,d\vec{l}\times\hat{r}}{r^2}$ into $\frac{I\,d\vec{l}\times\vec{r}}{r^3}$
Where $\hat{r}= \frac{\vec{r}}{r}$ .

$\vec{l}$ is in y-z plane. corresponds to (yc,zc) in the code.
and $\vec{r}$ corresponds to (xp-xc,yp-yc,zc)
Then calculate the cross product for the above two vector.

The integration is done by sum of components from all the coil segments.


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lookang

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4 Re: Magnetic field generated bar magnet

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Reply #3 on: September 24, 2009, 02:23:56 am » posted from:Fiesso D\'artico,Veneto,Italy

good sharing by W. K. Adams, Co-Director PhET Interactive Simulations University of Colorado, Boulder, USA
http://www.fisica.uniud.it/URDF/mptl14/dtlprogramme.htm
http://phet.colorado.edu/simulations/sims.php?sim=Faradays_Electromagnetic_Lab#topics

most popular hit
http://www.walter-fendt.de/ph14e/mfbar.htm

Gold mine find written by Wolfgang Christian, Francisco Esquembre, and Anne Cox
http://www.compadre.org/osp/document/ServeFile.cfm?ID=9414&DocID=1310#Doc1310

barmagnet.PNG (92.44 KB, 1021x603 - viewed 641 times.)
« Last Edit: September 24, 2009, 02:31:57 am by lookang »	Logged

lookang

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5 Re: Magnetic field generated bar magnet

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Reply #4 on: September 28, 2009, 09:00:19 am » posted from:Singapore,,Singapore

there is a remix version here
http://www.phy.ntnu.edu.tw/ntnujava/index.php?topic=1210msg4759;topicseen#msg4759

enjoy


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