NTNUJAVA Virtual Physics LaboratoryEnjoy the fun of physics with simulations! Backup site http://enjoy.phy.ntnu.edu.tw/ntnujava/
August 12, 2020, 03:01:13 am

An interdisciplinary approach. ...Wisdom

 Pages: [1]   Go Down
 Author Topic: Static equilibrium condition for coaxial wheels  (Read 8555 times) 0 Members and 1 Guest are viewing this topic. Click to toggle author information(expand message area).
Fu-Kwun Hwang
Hero Member

Offline

Posts: 3085

 « Embed this message on: February 24, 2007, 11:27:44 pm »

This is a coaxial wheel, with two different radius.
For the system to be in equilibrium, different mass m1,m2 need to be adjust at the right ratio.
You can change the ratio of the radius with slider bar, and drag m1 up/down with your mouse.
If you adjust m1, the program will calculate the balanced mass m2.
If you adjust m2, the system will not be in equilibrium.

The displayment in y-direction are dy1,dy2.
Find out the relation between dy2/dy1 to the ratio of the radius between those two wheels.
-*-

Embed a running copy of this simulation

Embed a running copy link(show simulation in a popuped window)
Full screen applet or Problem viewing java?Add http://www.phy.ntnu.edu.tw/ to exception site list