Spring force F=-k*x

Registed user can get files related to this applet for offline access.
Problem viewing java?Add http://www.phy.ntnu.edu.tw/ to exception site list
If java program did not show up, please download and install latest Java RUN TIME

First deag the box away from equilibrium point (horizontally). Then find out relations between the spring force and the displacement ...

The purpose for this applet is for you to find out how easily to create a java simulation with "Easy Java Simulation". Click the following link to find out how it was created with EJS.
(demonstration with flash)

The model is : dvx/dt = -k*x/m You can change the model.
For example change dvx/dt to (-k*x-0.1*vx)/m then you will have dampped oscillation.
Try it and click the run button to generate new simulation for you in the ejs popup window.

Related Topics
	Subject	Started by	Replies	Views	Last post
	Two blocks connected with spring with external force push Dynamics	Fu-Kwun Hwang	0	9220	February 26, 2007, 04:59:41 pm by Fu-Kwun Hwang
	Spring and constant friction force Dynamics	Fu-Kwun Hwang	0	7597	April 12, 2009, 12:02:17 am by Fu-Kwun Hwang
	Hozirontal spring and vertical spring Dynamics	Fu-Kwun Hwang	1	9946	April 05, 2010, 11:17:30 pm by Fu-Kwun Hwang
	Hozirontal spring and vertical spring dynamics	ahmedelshfie	0	2381	April 06, 2010, 11:42:18 pm by ahmedelshfie
	Spring force F=-k*x dynamics	ahmedelshfie	0	2467	May 11, 2010, 02:38:44 am by ahmedelshfie

	Author	Topic: Spring force F=-k*x (Read 38806 times)
0 Members and 1 Guest are viewing this topic. Click to toggle author information(expand message area).