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Author Topic: EM circular polarized wave  (Read 43144 times)
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Fu-Kwun Hwang
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on: October 22, 2005, 03:40:54 pm »

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The following applet show the E/B field for circular polarized wave.
The total E/B field is shown as default. You can select which component of E/B field to be shown. But do not turn on too many of them at the same time.



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Meika Resti
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Reply #1 on: April 27, 2010, 09:52:53 am » posted from:Surabaya,Jawa Timur,Indonesia

Hello sir, I'm curious about how the steps to make EM circular polarized wave simulation.Would you like to show it to me?
Thank you, Smiley
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lookang
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Reply #2 on: April 27, 2010, 02:04:57 pm » posted from:SINGAPORE,SINGAPORE,SINGAPORE

Hello sir, I'm curious about how the steps to make EM circular polarized wave simulation.Would you like to show it to me?
Thank you, Smiley

please download the source code to examine it.
the steps are many and perhaps almost impossible to write down every step clearly.
maybe you should look at the source code and articulate your learning difficulties so that we can understand what you want to learn. Smiley
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Meika Resti
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Reply #3 on: May 23, 2010, 07:08:48 pm » posted from:Surabaya,Jawa Timur,Indonesia

Sir, I have tried to make a EM circular wave, but the magnetic field can not appear as well as the electric field. I've been trying to find fault, but I have not found it.Please help me sir...
 Cry


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Fu-Kwun Hwang
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Reply #4 on: May 23, 2010, 11:32:07 pm » posted from:Taipei,T\'ai-pei,Taiwan

You need to know how to create a linear polarized wave first.

Assume the wave is moving in z direction, and electric field is in x direction (which means that magnetic field is in y direction).
Then
\vec{E}=E_x sin(k z-\omega t)
\vec{B}=B_y sin(k z-\omega t)

You can download the above simulation. Double click the jar file to run it , right click the mouse and select "open EJS model" to find out how it was created in EJS environment.
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Meika Resti
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Reply #5 on: May 24, 2010, 09:15:32 am » posted from:Surabaya,Jawa Timur,Indonesia

I know what you mean sir, and I've applied to my file. I've corrected my work, but I have not found my mistake...
I confuse sir...Help me... Cry
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Fu-Kwun Hwang
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Reply #6 on: May 24, 2010, 09:24:39 am » posted from:Taipei,T\'ai-pei,Taiwan

Please upload your ejs source (xml) file and explain what you have done.
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j.h.goh
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Reply #7 on: October 25, 2010, 04:10:52 pm » posted from:Liverpool,Liverpool,United Kingdom

Hi Sir,

I just want know, if I transmit a EM wave in a circular cavity, is it I will create a circular polarization?
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Fu-Kwun Hwang
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Reply #8 on: October 25, 2010, 05:36:16 pm » posted from:Taipei,T'ai-pei,Taiwan

The answer is No (normally).
Circular wave is due to there is 90 degree phase difference between two polarization waves.

You can create such phase difference if the wave speed is different when electric field is in different direction (different polarization).
i.e. two different refraction index values for different polarization.

You need to understand the meaning of polarization of wave to understand it.
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Reply #9 on: October 25, 2010, 06:30:37 pm » posted from:Liverpool,Liverpool,United Kingdom

Thank you for your reply Sir,

I have another idea, if I using the Vector Network Analyzer (VNA) to sweep the frequencies range in circular cavity, is it will generate a circular polarization?

Because different frequencies will have different wavelength, is this right?

or I could used a loop antenna to propagate the frequencies (from VNA) in the circular cavity, this will make different?



thank for all your helpful answer.
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Fu-Kwun Hwang
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Reply #10 on: October 25, 2010, 09:10:48 pm » posted from:,,Taiwan

Circular polarized wave means two wave with the same frequency but different polarization (Electric field are perpendicular to each other),
and the phase between those two electric field is 90 degree. It is circular polzrized if the amplitude of those two electric field are the same, otherwise, it is ellipse polarized.
 
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There is a better way to do it; find it. ..."Thomas Edison(1847-1931, American inventor, 1093 patients)"
 
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