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Author Topic: Ejs Open Source Heat capacity and Specific heat capacity Java Applet  (Read 7441 times)
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lookang
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on: August 29, 2012, 04:23:11 pm » posted from:SINGAPORE,SINGAPORE,SINGAPORE

Ejs Open Source Heat capacity and Specific heat capacity Java Applet by lookang, customized based on an earlier model http://www.compadre.org/osp/items/detail.cfm?ID=10071 by Wolfgang Christian.

Aims
1.   To investigate the relationship between the heat capacity of an object and the heat transferred per unit temperature change of the object.
2.   To infer the specific heat capacity of a substance from the heat capacity of an object of the same substance.

Syllabus Learning Outcome
This lesson exemplar addresses the following learning outcome:
-   define the terms heat capacity and specific heat capacity
-   recall and apply the relationship
   Thermal energy = mass X specific heat capacity X change in temperature


Assumption in the model
heat lost by the solid cylinder to the water is completely gain by the water, in other words, the container containing the water and solid cylinder is a perfect insulator.

Definition Equation 1
The heat capacity, C, of a body is defined as the amount of heat (or thermal energy) required to raise the temperature of a body by 1 oC (or 1 K).
therefore, heat capacity, C (units: J oC-1) = heat transferred (in J) / temperature change (in oC)

Definition Equation 2
The specific heat capacity, c, of a substance is defined as the amount of heat (or thermal energy) required to raise the temperature of a unit mass of the substance by 1 oC (or 1 K).
therefore specific heat capacity, c (in J oC-1kg-1 ) = heat transferred (in J) / temperature change (in oC) x mass of object (in kg)


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« Last Edit: August 29, 2012, 09:36:33 pm by lookang » Logged
lookang
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Reply #1 on: August 29, 2012, 04:32:56 pm » posted from:SINGAPORE,SINGAPORE,SINGAPORE

changes made:

design the water properties and rate of heat flow to depend on water instead of the older surrounding
made water mass and initial temperature variables
added hints and answers Qsolid and Qwater, notice Qsolid + Qwater = 0, assuming no heat Q loss to surrounding


data here https://docs.google.com/spreadsheet/ccc?key=0AjIvSg-TzZrZdFpVOXRTMlZrb2J1UEd5VThxZlJrQlE
m   C   Ti   Tf   Q = mc(tf-Ti)   Tf-Ti
0.1   385   20   52.6   1,255   32.6
0.1   385   20   61.9   1,613   41.9
0.1   385   20   71.2   1,971   51.2
0.1   385   20   80.6   2,333   60.6
0.1   385   20   89.9   2,691   69.9

work in progress
enjoy!


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« Last Edit: August 29, 2012, 09:36:16 pm by lookang » Logged
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