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Author Topic: A pendulum connected to a spring  (Read 14670 times)
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concord
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on: August 21, 2005, 08:09:59 pm »

A pendulum connected to a spring:

http://mw.concord.org/modeler1.3/mirror/mechanics/pendulum3.html

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Fu-Kwun Hwang
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Reply #1 on: February 17, 2010, 04:35:53 pm » posted from:Taipei,T\'ai-pei,Taiwan

The following is an EJS version of the above applet (with more options)

You can drag the spring, particle and the rod with mouse click/drag.
You can change spring constant k, mass m , spring length L, and damping constant b.
Enjoy it!

Embed a running copy of this simulation

Embed a running copy link(show simulation in a popuped window)
Full screen applet or Problem viewing java?Add http://www.phy.ntnu.edu.tw/ to exception site list
Press the Alt key and the left mouse button to drag the applet off the browser and onto the desktop. This work is licensed under a Creative Commons Attribution 2.5 Taiwan License
  • Please feel free to post your ideas about how to use the simulation for better teaching and learning.
  • Post questions to be asked to help students to think, to explore.
  • Upload worksheets as attached files to share with more users.
Let's work together. We can help more users understand physics conceptually and enjoy the fun of learning physics!
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Fu-Kwun Hwang
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Reply #2 on: October 24, 2011, 12:51:49 pm » posted from:Taipei,T'ai-pei,Taiwan

Equation used in the above simulation.
Assume angle \theta for the pendulum, angular velocity \omega=\frac{d\theta}{dt}
And \frac{d\omega}{dt}=calAplha(\theta)+ g\cos\theta+ -b\omega/m
where caAplha(\theta) calculate spring force and find it tangential component.

Code:
public double calAlpha (double c) {
 cs=Math.cos(c);
 sc=Math.sin(c);
 x=x2-R*cs;
 y=y2-R*sc;
 L=Math.sqrt((x-x1)*(x-x1)+(y-y1)*(y-y1));
 f=-k*(L-L0); fx=f*(x-x1);
 fy=f*(y-y1);
 n=-fx*cs-fy*sc;
 nx=-n*cs;
 ny=-n*sc;
 fx=fx-nx;
 fy=fy-ny;
 if(c>0)sign=-1;
 else sign=1;
 return sign*Math.sqrt(fx*fx+fy*fy)/I; // where I is the momentum of initial
}
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