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Author Topic: I'm soooooo lost on this one problem my teacher gave me; Forces on an Incline  (Read 3368 times)
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on: October 05, 2011, 11:31:27 pm » posted from:Doylestown,Pennsylvania,United States

I really need to know HOW to do this problem... and why...

He gave us an incline that is 30˚ with a box on top of the incline. When the Ms =0.5 and Mk = 0.3.
What happens?
-Does it move?
-If so, what's the acceleration?

So far :
I have drawn a force diagram that shows f to the left of the box, mg down from the box, and N (normal force) up from the box...
Fxnet=max and fynet=may

-fk=max and N-mg=may

is any of this right?... and if not... can someone PLEASE HELP.
Fu-Kwun Hwang
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Reply #1 on: October 06, 2011, 03:19:11 pm » posted from:Taipei,T'ai-pei,Taiwan

What are the meaning of Ms and Mk? Are they coefficient for static friction and kinetic friction?

You can calculate the component of gravitation force (mg) along the incline direction (m\,g\,\sin\theta)
and normal direction (m g Huh this is for your!) ,and find out the friction force.

Try to write down whatever you know and we will try to help you!
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