NTNUJAVA Virtual Physics LaboratoryEnjoy the fun of physics with simulations! Backup site http://enjoy.phy.ntnu.edu.tw/ntnujava/
July 20, 2018, 12:43:22 am

"There is nothing either good or bad, but thinking makes it so." ..."Shakespeare (154-1616, English dramatist and poet) "

 Pages: [1]   Go Down
 Author Topic: I'm soooooo lost on this one problem my teacher gave me; Forces on an Incline  (Read 3785 times) 0 Members and 1 Guest are viewing this topic. Click to toggle author information(expand message area).
Stuckonphysics
Newbie

Offline

Posts: 1

 « Embed this message on: October 05, 2011, 11:31:27 pm » posted from:Doylestown,Pennsylvania,United States

I really need to know HOW to do this problem... and why...

He gave us an incline that is 30˚ with a box on top of the incline. When the Ms =0.5 and Mk = 0.3.
What happens?
-Does it move?
-If so, what's the acceleration?

So far :
I have drawn a force diagram that shows f to the left of the box, mg down from the box, and N (normal force) up from the box...

Then,
Fxnet=max and fynet=may

So,
-fk=max and N-mg=may

 Logged
Fu-Kwun Hwang
Hero Member

Offline

Posts: 3080

 « Embed this message Reply #1 on: October 06, 2011, 03:19:11 pm » posted from:Taipei,T'ai-pei,Taiwan

What are the meaning of Ms and Mk? Are they coefficient for static friction and kinetic friction?

You can calculate the component of gravitation force (mg) along the incline direction ($m\,g\,\sin\theta$)
and normal direction (m g this is for your!) ,and find out the friction force.

Try to write down whatever you know and we will try to help you!
 Logged
 Pages: [1]   Go Up
"There is nothing either good or bad, but thinking makes it so." ..."Shakespeare (154-1616, English dramatist and poet) "