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Progress is impossible without change; and those who cannot change their minds cannot change anything. ..."George Bernard Shaw(1865-1950, Irish dramatist, essayist and critic, Nobel Prize for Literature 1925)"

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 Author Topic: I'm soooooo lost on this one problem my teacher gave me; Forces on an Incline  (Read 3654 times) 0 Members and 1 Guest are viewing this topic. Click to toggle author information(expand message area).
Stuckonphysics
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 « Embed this message on: October 05, 2011, 11:31:27 pm » posted from:Doylestown,Pennsylvania,United States

I really need to know HOW to do this problem... and why...

He gave us an incline that is 30˚ with a box on top of the incline. When the Ms =0.5 and Mk = 0.3.
What happens?
-Does it move?
-If so, what's the acceleration?

So far :
I have drawn a force diagram that shows f to the left of the box, mg down from the box, and N (normal force) up from the box...

Then,
Fxnet=max and fynet=may

So,
-fk=max and N-mg=may

is any of this right?... and if not... can someone PLEASE HELP.
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Fu-Kwun Hwang
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 « Embed this message Reply #1 on: October 06, 2011, 03:19:11 pm » posted from:Taipei,T'ai-pei,Taiwan

What are the meaning of Ms and Mk? Are they coefficient for static friction and kinetic friction?

You can calculate the component of gravitation force (mg) along the incline direction ($m\,g\,\sin\theta$)
and normal direction (m g this is for your!) ,and find out the friction force.

Try to write down whatever you know and we will try to help you!
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Progress is impossible without change; and those who cannot change their minds cannot change anything. ..."George Bernard Shaw(1865-1950, Irish dramatist, essayist and critic, Nobel Prize for Literature 1925)"
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