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Author Topic: Ejs Open Source Newton's Mountain Projectile Orbits Model java applet  (Read 14709 times)
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lookang
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on: May 20, 2011, 10:44:32 pm » posted from:Singapore,,Singapore

Ejs Open Source Newton Mountain Model java applet by Todd Timberlake remixed by lookang
Ejs Open Source Newton's Mountain Projectile Orbits Model java applet
reference:
http://www.compadre.org/osp/items/detail.cfm?ID=9391
http://www.phy.ntnu.edu.tw/ntnujava/index.php?topic=398.msg7167#msg7167



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Press the Alt key and the left mouse button to drag the applet off the browser and onto the desktop. This work is licensed under a Creative Commons Attribution 2.5 Taiwan License
  • Please feel free to post your ideas about how to use the simulation for better teaching and learning.
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Let's work together. We can help more users understand physics conceptually and enjoy the fun of learning physics!


* Ejs_Open_Source_Newton_Mountain_Model_java_applet.png (163.02 KB, 658x608 - viewed 572 times.)
« Last Edit: October 09, 2012, 03:17:10 pm by lookang » Logged
lookang
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Reply #1 on: May 20, 2011, 10:48:30 pm » posted from:Singapore,,Singapore

changes:
made sliders and fields conform to my design preference
redo for SI units for closer to sg syllabus instead of arbitrary units originally made
22May2011
add earth picture
add panel of x,y,vx,vy,ax,ay for calculating values to coincident with Earth data
add trace instead of the older trail that can display older data
rotate newton's diagram by 5 degree to coincident with x=0, instead of the older 0.1*R
add time
change to acceleration instead of force
24 May 2011
add multiple representation of versus time and distance from center of earth
add menu for circular motion R,2R,3R and escape velocity at theta 0,45,90
26 May 2011
minor changes on menu list name R_earth instead of 6.38E06 as suggested by leongster
made theta = blank
add check box on the bottom panel for quick access as suggested by leongster.
07 june2011
added reference frame space and earth for earth to rotate if frame is space
added a few geostationary orbits and non-geostationary
remove newton mountain and replace with a rectangle


to do
newton mountain gif to make background transparent


challenge:
some problem detecting the boundary of earth solved

double hitEarth (double x, double y) {
  if (!pass) {
   return x*x+y*y-R*R;}
  else {
   return 0;}
}
« Last Edit: June 07, 2011, 08:31:23 pm by lookang » Logged
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Reply #2 on: May 23, 2011, 09:26:45 pm » posted from:Singapore,,Singapore

question.
what is the velocity of the projectile if it is launch horizontally at the surface of the Earth?

hint: use circular motion equation to find the v!

enjoy!

answer:
7920.05 m/s

try it with the this customized with Earth data simulation Smiley


* circular_motion_around_earth_what_velcocity.png (200.94 KB, 758x608 - viewed 524 times.)

*** There are 3 more attached files. You need to login to acces it!
« Last Edit: July 25, 2011, 12:12:14 pm by lookang » Logged
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Reply #3 on: October 08, 2012, 05:32:34 pm » posted from:SINGAPORE,SINGAPORE,SINGAPORE

added http://weelookang.blogspot.sg/2011/05/ejs-open-source-newtons-mountain.html

Orbits round the Earth

An object projected horizontally near the Earth’s surface follows a parabolic trajectory. As the velocity of projection increases, there will be an occasion in which the trajectory follows the curvature of the Earth’s surface. If air resistance is negligible, the object will orbit round the Earth and will never meet the Earth’s surface.




speed of cannonball at 0 km/hr launched horizontally from newton's very tall mountain, resulting in trajectory that hits Earth surface.






speed of cannonball at 1 000 km/hr launched horizontally from newton's very
tall mountain, resulting in trajectory that hits Earth surface.






speed of cannonball at 2 000 km/hr launched horizontally from newton's very
tall mountain, resulting in trajectory that hits Earth surface.






speed of cannonball at 3 000 km/hr launched horizontally from newton's very
tall mountain, resulting in trajectory that hits Earth surface.






speed of cannonball at 4 000 km/hr launched horizontally from newton's very
tall mountain, resulting in trajectory that hits Earth surface.






speed of cannonball at 5 000 km/hr launched horizontally from newton's very
tall mountain, resulting in trajectory that hits Earth surface.






speed of cannonball at 6 000 km/hr launched horizontally from newton's very
tall mountain, resulting in trajectory that hits Earth surface.






speed of cannonball at 7 000 km/hr launched horizontally from newton's very
tall mountain, resulting in trajectory that does NOT hit the Earth surface.








speed of cannonball at 7 300 km/hr launched horizontally from newton's very
tall mountain, resulting in trajectory orbit that does NOT hit the Earth surface that is a approximately a circular orbit.






speed of cannonball at 8 000 km/hr launched horizontally from newton's very
tall mountain, resulting in trajectory orbit that does NOT hit the Earth surface.






speed of cannonball at 9 000 km/hr launched horizontally from newton's very
tall mountain, resulting in trajectory orbit that does NOT hit the Earth surface.






speed of cannonball at 11 200 km/hr launched horizontally from newton's very
tall mountain, resulting in trajectory that does NOT hit the Earth surface and escape from the Earth's gravitational pull








plot of kinetic energy  E_{K}, gravitational potential energy,  E_{P} and total Energy  Eversus distance away from centre of earth, r at R= Re






plot of kinetic energy  E_{K}, gravitational potential energy,  E_{P} and total Energy  Eversus distance away from centre of earth, r at R= Re, R= 2*Re






plot of kinetic energy  E_{K}, gravitational potential energy,  E_{P} and total Energy  Eversus distance away from centre of earth, r at R= Re, R= 2*Re, R=3*Re






plot of kinetic energy  E_{K}, gravitational potential energy,  E_{P} and total Energy  Eversus distance away from centre of earth, r at R= Re, R= 2*Re, R=3*Re and lastly R = geostationary radius



« Last Edit: October 08, 2012, 05:34:28 pm by lookang » Logged
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Reply #4 on: October 09, 2012, 03:19:54 pm » posted from:SINGAPORE,SINGAPORE,SINGAPORE

Question01
An
 earth satellite of mass 200 kg lost energy slowly through atmospheric
resistance and fell from an orbit of radius 8.0 x 106 m to 7.8 x 106 m.
Calculate the changes in the potential, kinetic and total energies of
the satellite during this transition period.

Answers: ( -2.57E8 J, 1.28E8 J, -1.28E8 J ) where E denotes x10



Solution:

a)

\Delta PE\ = - G \frac{M m}{r_2}\ - ( - G \frac{M m}{r_1}\ ) \Delta PE\ = - 6.67x10^{-11} \frac{(6.0x10^{24}) (200)}{7.8x10^6}\ - ( - 6.67x10^{-11} \frac{(6.0x10^{24}) (200)}{8.0x10^6}\ ) \Delta PE\ = -2.57x10^8 J

b)

Assuming the orbits are in circular motion as it decays from r_1 = 8.0 x 10^6 to r_2 = 7.8 x 10^6

equation  G \frac{M m}{r^2}\ =  \frac{m v^2}{r}\ can be assumed to be valid to approximate this motion

Thus, \Delta KE\ =\frac{1}{2}\ m v_2^2 - \frac{1}{2}\ m v_1^2

\Delta KE\ =\frac{1}{2}\ mG \frac{M}{r_2}\ - \frac{1}{2}\ mG \frac{M}{r_1}\ 



\Delta KE\ =\frac{1}{2}\ (200)(6.67x10^{-11}) \frac{6.0x10^{24}}{7.8x10^6}\ - \frac{1}{2}\ (200)(6.67x10^{-11}) \frac{6.0x10^{24}}{8.0x10^6}\ 

\Delta KE\ = 1.28x10^8 J 

c)

since  TE = PE + KE

 TE = -2.57x10^8 + 1.28x10^8

 TE = - 1.28x10^8 J



check:

This answer  TE = - 1.28x10^8 J can also be verified from the formula relationship on page Newton's Mountain Projectile Orbits which is not intended to be memorized.








Using the simulation:








using R = 8.0X10^6 , v = 7072.8 m/s for circular motion orbit, you can
get for satellite m = 1kg, KE = 2.501X10^7 J, PE = -5.002X10^7 J and TE =
-2.501X10^7 J








using R = 7.8X10^6 , v = 7162.9 m/s for circular motion orbit, you can
get for satellite m = 1kg, KE = 2.565X10^7 J, PE = -5.131X10^7 J and TE =
-2.565X10^7 J

 Thus,  

ΔKE = 200(2.565X10^7 - 2.501X10^7) = 1.28X10^8 J



ΔPE = 200(-5.131X10^7 - (-5.002X10^7)) = -2.58X10^8 J



ΔTE = 1.28X10^8 + (-2.58X10^8) = 1.30X10^8 J



where the slight difference is due to carry over error from the significant figures of the computer model. 















reference:

http://commons.wikimedia.org/wiki/File:R_%3D_geo_Re_2012-10-08_1809.png#.7B.7Bint:filedesc.7D.7D




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Reply #5 on: June 17, 2013, 07:34:00 am » posted from:SINGAPORE,SINGAPORE,SINGAPORE

taking the codes from fu-kwun hwang model here http://www.phy.ntnu.edu.tw/ntnujava/index.php?topic=2083.0
i added the ability to fire and circular from this model space shuttle motion with impulse and added into the model above Ejs Open Source Newton's Mountain Projectile Orbits Model java applet http://www.phy.ntnu.edu.tw/ntnujava/index.php?topic=2204.0 !

enjoy!

http://weelookang.blogspot.sg/2011/05/ejs-open-source-newtons-mountain.html
added ability to fire to add velocity to a achieve eclipse orbit and select circular to achieve circular orbit by applying impulse in directions to get velocity at the correct speed and direction, perpendicular to radius. this feature helps in the learning of energies change as satellite move from one circular orbit to another circular as requested by soo kok.
https://dl.dropboxusercontent.com/u/44365627/lookangEJSworkspace/export/ejs_NewtonsMountainwee06.jar
author: timberlake, lookang and fu-kwun hwang

many thanks to prof fu-kwun hwang and his physics validated codes to help ordinary teachers make wonderful models for enhanced teaching and learning for the benefit of all humankind!

licensed creative commons attribution.


* mountain_6_2013-06-13_1731.png (101.19 KB, 808x601 - viewed 475 times.)
« Last Edit: June 17, 2013, 07:43:41 am by lookang » Logged
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