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"Progress, therfore, is not and accident,¡K" ..."Herbert Spencer(1820-1903, British philosopher)"
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Author Topic: operational amplifier simulation  (Read 16482 times)
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alfalion
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on: February 24, 2011, 12:03:00 am » posted from:Baia Mare,Maramures,Romania

Hi there. I'm new to this forum. I like electronics very much and i was wondering if a simulation of operational amplifiers can be made. Something like changing the input voltage or some resistor and see what you get at the output using EJS.
Some of the most important opamp categories can be found here
So is it possible?
Thank you.
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Fu-Kwun Hwang
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Reply #1 on: February 24, 2011, 11:31:28 pm » posted from:Taipei,T\'ai-pei,Taiwan

I hope the following simulation is what you need!
You can use sliders to change R1,R2, Vin.
Click invert to find the circuit type similar to your case!

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* ejs_operationalAmplifier.jpg (18.1 KB, 673x392 - viewed 521 times.)
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alfalion
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Reply #2 on: February 25, 2011, 05:00:24 pm » posted from:Baia Mare,Maramures,Romania

Yes, this is what i was wondering about. Thanx.
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Tminus
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Reply #3 on: June 08, 2011, 04:52:02 pm » posted from:Satu Mare,Satu Mare,Romania

Hello Mr. Fu-Kwun Hwang, can you explain or comment the variables (what they do) used for this simulation? I want to better understand this simulation. Thankyou very much.
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Fu-Kwun Hwang
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Reply #4 on: June 08, 2011, 05:52:58 pm » posted from:Taipei,T'ai-pei,Taiwan

The key point is: the same current flow through both resistors R_1,R_2.

For non-invert case:
 V_{out}=I\,(R_1+R_2), \qquad V_{in}=I\, R_1
so V_{out}=\frac{R_1+R_2}{R_1} V_{in}=(1+\frac{R_2}{R_1}) V_{in}


For invert case:

 V_{out}= -I\, R_2, \qquad V_{in}=I\, R_1
so V_{out}=-\frac{R_2}{R_1}\, V_{in}
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srisak31
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Reply #5 on: October 14, 2015, 03:18:15 pm » posted from:BANG BUA THONG,NONTHABURI,THAILAND

 Cheesy
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chamDz
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Reply #6 on: October 26, 2015, 05:00:24 pm » posted from:,,Sri Lanka

i have some concerns regarding this  Embarrassed
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