NTNUJAVA Virtual Physics LaboratoryEnjoy the fun of physics with simulations! Backup site http://enjoy.phy.ntnu.edu.tw/ntnujava/
January 23, 2019, 08:40:19 am

Establish Good support system. ...Wisdom

 Pages: [1]   Go Down
 Author Topic: Relation between displacement current and electric field with R-C circuit  (Read 18022 times) 0 Members and 1 Guest are viewing this topic. Click to toggle author information(expand message area).
Fu-Kwun Hwang
Hero Member

Offline

Posts: 3080

 « Embed this message on: February 15, 2011, 11:20:41 pm » posted from:Taipei,T\'ai-pei,Taiwan

The electric displacement field is defined as:
$\boldsymbol{D} = \varepsilon_0 \boldsymbol{E} + \boldsymbol{P}\ =\varepsilon \boldsymbol{E}$.

where:
ε0 is the permittivity of free space
E is the electric field intensity
P is the polarization of the medium

The folliwing use RC-circuit to show relation between displacement current and electric field.

To make it easier, the value of ε0 is assigned as 0.5

Un-check the off check box to connect the DC voltage source to the RC circuit (ON).
k is the dielectric constant $\varepsilon/\varepsilon_0$.
You can adjust voltage source Vs, resistance R, capacitance C.

Embed a running copy of this simulation

Embed a running copy link(show simulation in a popuped window)
Full screen applet or Problem viewing java?Add http://www.phy.ntnu.edu.tw/ to exception site list