NTNUJAVA Virtual Physics Laboratory
Enjoy the fun of physics with simulations!
Backup site http://enjoy.phy.ntnu.edu.tw/ntnujava/
September 22, 2017, 10:16:21 pm *
Welcome, Guest. Please login or register.
Did you miss your activation email?

Login with username, password and session length
 
   Home   Help Search Login Register  
"If I have a thousand ideas and only one turns out to be good, I am satisfied." ..."Alfred Nobel(1833-1896, Swedish inventor, chemist, philanthropist)"
Google Bookmarks Yahoo My Web MSN Live Netscape Del.icio.us FURL Stumble Upon Delirious Ask FaceBook

Pages: [1]   Go Down
  Print  
Author Topic: Ejs Open source Primary Distance & Speed time java applet  (Read 9904 times)
0 Members and 1 Guest are viewing this topic. Click to toggle author information(expand message area).
lookang
Moderator
Hero Member
*****
Offline Offline

Posts: 1784


http://weelookang.blogspot.com


WWW
«
Embed this message
on: January 10, 2011, 08:50:50 am » posted from:SINGAPORE,SINGAPORE,SINGAPORE

Ejs Open source Displacement & Velocity time java applet
Ejs Open source Primary Distance & Speed time java applet

variant simulation for Primary Maths.
http://www.phy.ntnu.edu.tw/ntnujava/index.php?topic=750.0

finer customized for Primary school maths

Embed a running copy of this simulation

Embed a running copy link(show simulation in a popuped window)
Full screen applet or Problem viewing java?Add http://www.phy.ntnu.edu.tw/ to exception site list
Press the Alt key and the left mouse button to drag the applet off the browser and onto the desktop. This work is licensed under a Creative Commons Attribution 2.5 Taiwan License
  • Please feel free to post your ideas about how to use the simulation for better teaching and learning.
  • Post questions to be asked to help students to think, to explore.
  • Upload worksheets as attached files to share with more users.
Let's work together. We can help more users understand physics conceptually and enjoy the fun of learning physics!

« Last Edit: January 12, 2011, 04:02:05 pm by lookang » Logged
lookang
Moderator
Hero Member
*****
Offline Offline

Posts: 1784


http://weelookang.blogspot.com


WWW
«
Embed this message
Reply #1 on: January 10, 2011, 08:53:48 am » posted from:SINGAPORE,SINGAPORE,SINGAPORE

changes


1 remove acceleration according to primary school teacher.
2 unit in km/h instead of m/s according to primary school teacher.
3 further bug reduction
4 axis for x is further refine to follow
xming = Math.min(x1,xmin);
xming = Math.min(x2,xming); // for maximum view instead of autoscale which is suppose to be difficult for young minds
5 fix PY1[1] and PY2[1] at the top left corner to follow the distance of the rectangle
6 fix the time to reflect the distance as accurate as possible for given t = 0.00s
7 use // screen view
if(x1if(x1>xmax) xmax*=1.2;
if(x2if(x2>xmax) xmax*=1.2; instead of 4
8 change context to cars (from microsoft clipart) as to travel in km/h
9 added town A and B selectable to a maximum of 10 to 1000 km to suit most problem.
10 time is input field to suit questions that require going backwards in time



* redcar.png (29.06 KB, 289x289 - viewed 317 times.)

* yellowcar.png (43.49 KB, 385x193 - viewed 302 times.)
« Last Edit: January 11, 2011, 02:20:01 pm by lookang » Logged
lookang
Moderator
Hero Member
*****
Offline Offline

Posts: 1784


http://weelookang.blogspot.com


WWW
«
Embed this message
Reply #2 on: January 12, 2011, 03:52:25 pm » posted from:SINGAPORE,SINGAPORE,SINGAPORE

Question 1
RED drove from Town A to Town B at a uniform speed. At 2/3 of the journey, RED passed his neighbor, YELLOW, who started from Town A earlier. YELLOW was driving his car at an average speed of 72km/h. 3 hours later, RED arrived at Town B. YELLOW was still 40km away from Town B. What was the distance between Town A and Town B?

Solution
72 x 3 = 216
216 + 40 = 256
256 x 3 = 768 km





* Math1.png (32.42 KB, 504x494 - viewed 259 times.)
Logged
lookang
Moderator
Hero Member
*****
Offline Offline

Posts: 1784


http://weelookang.blogspot.com


WWW
«
Embed this message
Reply #3 on: January 12, 2011, 03:54:54 pm » posted from:SINGAPORE,SINGAPORE,SINGAPORE

Question 2
A RED car was on its way from Town A to Town B. After covering 2/5 of its journey, it passed a YELLOW car which was moving at an average speed of 70 km/h. 5 h later, the RED car reached its destination, but the YELLOW car was still 28 km from town B. If the YELLOW car had also started from town A, how long would it take to travel from Town A to Town B?

Solution
70 x 5 = 350
350 + 28 = 378
378 ÷ 3 = 126
126 x 5 = 630
630 ÷ 70 = 9 h


* Math2.png (34.31 KB, 508x503 - viewed 298 times.)
Logged
lookang
Moderator
Hero Member
*****
Offline Offline

Posts: 1784


http://weelookang.blogspot.com


WWW
«
Embed this message
Reply #4 on: January 12, 2011, 03:57:00 pm » posted from:SINGAPORE,SINGAPORE,SINGAPORE

Question 3
RED and YELLOW have a race. RED cycles at a speed of 12 km/h. YELLOW cycles at speed of 16km/h. If YELLOW lets RED start 40 min before him, how long will YELLOW take to catch up with RED?

Solution
16 – 12 = 4
12 x(40/60)  = 8
8 ÷ 4 = 2 h
 


* Math3.png (31.77 KB, 511x499 - viewed 304 times.)
Logged
lookang
Moderator
Hero Member
*****
Offline Offline

Posts: 1784


http://weelookang.blogspot.com


WWW
«
Embed this message
Reply #5 on: January 12, 2011, 03:58:18 pm » posted from:SINGAPORE,SINGAPORE,SINGAPORE

Question 4
The distance between Town A and Town B was 540 km. RED car took 6 hours to travel from Town A to Town B. A YELLOW car took 12 hours to travel from Town B to Town A. Both the RED car and the YELLOW car started their journey at noon. At what time would they pass each other along the same road?

12 X 6 = 72   
   6 + 12 = 18   
   72/18  = 4   
    They will pass each other at 4 p.m.


* Math4.png (35.35 KB, 507x496 - viewed 281 times.)
Logged
lookang
Moderator
Hero Member
*****
Offline Offline

Posts: 1784


http://weelookang.blogspot.com


WWW
«
Embed this message
Reply #6 on: January 12, 2011, 04:01:02 pm » posted from:SINGAPORE,SINGAPORE,SINGAPORE

Question 5
A RED car took 2 h to travel from town X to town Y. His average speed for the whole journey was 40 km/h. For the first  of the journey, he traveled at an average speed of 50 km/h. Find his average speed for the second part of the journey



Solution
   2  X 40 = 100 km
   100 X (1/4)  = 25 km
   100 – 25 = 75 km               
   time taken for (1/4)  of journey   = 25/50          
               =  1/2 h
   time taken for 2nd part of journey   = 2.5  – 0.5   
                  = 2h
   Average speed = 75km /  2            
          = 37.5km/h            

or   2.5  X 40 = 100 km
   100 x (3/4) = 75
75 ÷ 2 = 37.5 km/h




* Math5.png (33.59 KB, 515x497 - viewed 312 times.)
Logged
Pages: [1]   Go Up
  Print  
"If I have a thousand ideas and only one turns out to be good, I am satisfied." ..."Alfred Nobel(1833-1896, Swedish inventor, chemist, philanthropist)"
 
Jump to:  


Related Topics
Subject Started by Replies Views Last post
Ejs Open source Displacement & Velocity time graph for area & dx/dt java applet
Collaborative Community of EJS
lookang 17 26393 Last post December 27, 2010, 07:55:30 pm
by ahmedelshfie
Ejs open source Division java Applet for Primary Mathematics with scaffolds
Collaborative Community of EJS
lookang 14 18482 Last post June 22, 2009, 06:02:24 pm
by Fu-Kwun Hwang
Ejs Open Source Ideal Gas Model with Maxwell Distribution of Speed Java Applet
Collaborative Community of EJS
lookang 2 7421 Last post April 26, 2010, 08:31:24 pm
by ahmedelshfie
Ejs Open Source Reaction Time Measurement Traffic Light Model Java Applet
Collaborative Community of EJS
lookang 5 9980 Last post October 03, 2011, 08:47:30 pm
by lookang
Primary School Speed Time
Collaborative Community of EJS
engrg1 6 9842 Last post February 08, 2013, 07:01:56 pm
by engrg1
Powered by MySQL Powered by PHP Powered by SMF 1.1.13 | SMF © 2006-2011, Simple Machines LLC Valid XHTML 1.0! Valid CSS!
Page created in 0.06 seconds with 23 queries.since 2011/06/15