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Give me a standpoint and I will move the earth. ...Archimedes (287-212BC)
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Author Topic: Gravitational forces  (Read 19972 times)
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v_iwaszczenko
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on: May 18, 2005, 07:09:25 am »

Is there an applet that simulates the orbits of the planets around the sun which is based on the equation for gravitational force GMm/r^2. This equation does not allow for the position of the planet in relation to the sun. That is earth could be at declination of -12 and at a position of 90 degrees and Mars could be at declination +5 and position 270 degrees. How is the net resolution of these forces handled?
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Fu-Kwun Hwang
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Reply #1 on: June 04, 2009, 02:46:27 pm » posted from:Taipei,T\'ai-pei,Taiwan

The mass of the sun is much larger than all the planets.
For example: the mass of the sun is 10^6 times mass of the earth.

So the interaction forces between planets are much smaller than interaction force between planet and the sun.

It means that the motion for each planet are all similar.
You can check out Kepler Motion or How to determined the trajectory of a planetary motion?
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Jennifer Barker
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Reply #2 on: January 09, 2017, 12:54:46 pm » posted from:Karachi,Sindh,Pakistan

The gravitational force  is a force  that draws in any question with mass. Each question, including you, Dissertation Writers UK is pulling on each other protest in the whole universe! This is called Newton's Universal Law of Gravitation.
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Give me a standpoint and I will move the earth. ...Archimedes (287-212BC)
 
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