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 Author Topic: Condition for stable equilibrium  (Read 34712 times) 0 Members and 2 Guests are viewing this topic. Click to toggle author information(expand message area).
Fu-Kwun Hwang
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 « Embed this message on: May 16, 2005, 07:59:39 am »

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Under the influence of gravity: the condition for stable equilibrium is
the center of gravity [b:22e0df7a63](c.g.)[/b:22e0df7a63] must be lower than the supporting point. (potential energy is minimum)

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lookang
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 « Embed this message Reply #1 on: February 11, 2010, 05:38:31 pm » posted from:SINGAPORE,SINGAPORE,SINGAPORE

great applet! i am trying to re-customize it to allow for 2 mass variables, 2 distances.

i define
d(omega)/dt = -(m1*g*(xl-x) +m2*g*(xr-x))/(inertia1+inertia2)

but it didn't evolution as i thought it would in real life.

i will work on it again.

btw, the time is off by one hour, it is 6.39 pm instead of the time shown 5.39pm. for ur info
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Fu-Kwun Hwang
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 « Embed this message Reply #2 on: February 11, 2010, 05:49:54 pm » posted from:Taipei,T\'ai-pei,Taiwan

If the center of gravity for those two objects is (xc,yc) and the supporting point is (x,y)
The conditions for stable equilibrium is (x=xc and y>yc) when supporting bar is horizontal.

The who system can be model like a pendulum, the supporting point is the tip of the pendulum, and assume all the mass is located at the center of the gravity.

For the time offset:
then click Look and Layout Preferences from the left menu.
You will find "Time Offset:" in the table,  change the value from 0 to 1 (or click auto detect link)
then click Change Profile button , then everything should be fine for your time format.
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lookang
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 « Embed this message Reply #3 on: February 12, 2010, 07:53:20 am » posted from:SINGAPORE,SINGAPORE,SINGAPORE

If the center of gravity for those two objects is (xc,yc) and the supporting point is (x,y)
The conditions for stable equilibrium is (x=xc and y>yc) when supporting bar is horizontal.

The who system can be model like a pendulum, the supporting point is the tip of the pendulum, and assume all the mass is located at the center of the gravity.

This is amazing insight, thanks for the tips, looks like i need to change quite a bit of evolution equation....LOL
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Fu-Kwun Hwang
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 « Embed this message Reply #4 on: February 12, 2010, 10:18:43 am » posted from:Taipei,T\'ai-pei,Taiwan

The first applet was model in the same way. Use the center of gravity relative to the supporting point as a pendulum to model the system. You can check out how it was done.
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Wisdom is to bring the best out of our students. ...Wisdom