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Simplicity is the ultimate sophistication. ..."da Vinci (1452-1519, Italian artist, sculptor, painter, architect, engineer and scientist) "

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 Author Topic: Physics of rainbow (EJS version)  (Read 8704 times) 0 Members and 1 Guest are viewing this topic. Click to toggle author information(expand message area).
ahmedelshfie
Ahmed
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 « Embed this message on: May 12, 2010, 01:41:03 am » posted from:,,Brazil

This applet is Physics of rainbow (EJS version)
Created by prof Hwang modified by Ahmed
Original project Physics of rainbow (EJS version)
I'm really wonder from this simulation how much is fantastic

Embed a running copy of this simulation

Embed a running copy link(show simulation in a popuped window)
Full screen applet or Problem viewing java?Add http://www.phy.ntnu.edu.tw/ to exception site list
• Please feel free to post your ideas about how to use the simulation for better teaching and learning.
• Post questions to be asked to help students to think, to explore.
• Upload worksheets as attached files to share with more users.
Let's work together. We can help more users understand physics conceptually and enjoy the fun of learning physics!
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ahmedelshfie
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 « Embed this message Reply #1 on: May 12, 2010, 01:47:26 am » posted from:,,Brazil

You can click the "real intensity" checkbox to find out the relative intensity for different paths.
You can drag the black square near the left side of the simulation to drag those rays up and down.

You might notice that intensity for incoming rays are not the same. It is indicated that the cross section are not the same for different ray.
If the ray is off by the center of the water drop by distance b, and the rasius of the circle is R.
The incident angle $\theta$, where$\sin\theta=b/R$, the effective cross section is proportional to $\cos\theta$

If the index of refraction is n, the refracted angle$\phi$, where$\sin\phi=b/R/n ( i.e. sin\theta= n \sin\phi)$.

If the intensity of incoming ray is $I$, then the intensity for the reflected ray(s wave) is $I_r=\frac{\sin^2(\theta-\phi)}{\sin^2(\theta+\phi)} I$ and the intensity for refracted light is $I$'$=$$I-I_r$

The above formulas are used to calculate the intensity for different ray.
You are welcomed to check out Physics of Rainbow for more in depth discussion about rainbow
 « Last Edit: May 12, 2010, 02:17:27 am by ahmedelshfie » Logged
ahmedelshfie
Ahmed
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 « Embed this message Reply #2 on: May 12, 2010, 10:15:25 am » posted from:Uberaba,Minas Gerais,Brazil

Prof Hwang please i had a problem for typing last equation like in page
Of original project can you solve it please
Thank you
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Fu-Kwun Hwang
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 « Embed this message Reply #3 on: May 12, 2010, 08:56:50 pm » posted from:Taipei,T\'ai-pei,Taiwan

This forum support TeX syntax for mathematics equation.
It is similar to wiki mathematics equation.
However, the equation is enclose between dollar signs.
Please check out for syntax http://en.wikipedia.org/wiki/Math_markup
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ahmedelshfie
Ahmed
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 « Embed this message Reply #4 on: May 12, 2010, 11:30:28 pm » posted from:,,Brazil

Yes i check I'm typing equations right I'm just meet a problem in
Last symbol after $I$ direct is this only the problem but equations i typing right
I will attach image and mark what the problem for you check prof
 image equation1.GIF (24.29 KB, 718x557 - viewed 531 times.) Logged
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Simplicity is the ultimate sophistication. ..."da Vinci (1452-1519, Italian artist, sculptor, painter, architect, engineer and scientist) "