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 Author Topic: A loop rotating in a magnetic field (How electric power generator works!  (Read 8497 times) 0 Members and 1 Guest are viewing this topic. Click to toggle author information(expand message area).
ahmedelshfie
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 « Embed this message on: April 12, 2010, 02:17:41 am »

This applet created by Prof Hwang
Modified by my self
I add tow bars for (sc) and (time)
Original project:A loop rotating in a magnetic field (How electric power generator works!)

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 loop.jpg (39.18 KB, 636x573 - viewed 512 times.) « Last Edit: April 21, 2010, 12:07:55 pm by ahmedelshfie » Logged
ahmedelshfie
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 « Embed this message Reply #1 on: April 21, 2010, 02:42:23 am »

When a loop rotating in a uniform magnetic field.
The magnetic flux is changing which will induce electric field along the loop (produce voltage).
If the loop is rotating with constant angular velocity \omega . (The angle is \omega t)
The magnetic flux in the loop will be $\Psi =\int \vec{B}\cdot d\vec{A}= B A cos(\omega t)$
So the induced emf $= -\frac {d\Psi}{dt}=B A \omega sin(\omega t)$

The following simulation show how it works dynamically.
 « Last Edit: May 18, 2010, 07:52:55 am by ahmedelshfie » Logged
Fu-Kwun Hwang
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 « Embed this message Reply #2 on: April 21, 2010, 10:06:44 am »

You need to add TeX equation between $to be displayed as equation. I have added dollar sign for the above posted message for you!  Logged ahmedelshfie Moderator Hero Member Offline Posts: 954  « Embed this message Reply #3 on: April 21, 2010, 12:21:11 pm » Yes prof,, i had the text information and equations from topic http://www.phy.ntnu.edu.tw/ntnujava/index.php?topic=912.0 So i think I'm make wrong right  « Last Edit: April 22, 2010, 09:47:16 am by ahmedelshfie » Logged Fu-Kwun Hwang Administrator Hero Member Offline Posts: 3086  « Embed this message Reply #4 on: April 21, 2010, 04:50:40 pm » You need to add dollar sign for those equations. Otherwise, those equation would not be convert to image. The following is what you have copied. Code: This simulation shows a current loop in uniform magnetic field. The black arrows show the force due to magnetic field on the loop. \vec{F}= q \vec{v} \times \vec{B} or \vec{F}= I \int d\vec{\ell} \times \vec{B} The magnetic field in in the +Z direction if Bz>0. Then ,torque for the loop is calculated from definition \vec{\tau}=\vec{r}\times\vec{F} Because the current flow in the same counter-clockwise direction. The force on the loop change sign during each helf cycle. If we current reverse direction during each helf cycle, the following device can turn into a motor. A voltage source is needed in the loop to drive the current.  Logged ahmedelshfie Moderator Hero Member Offline Posts: 954  « Embed this message Reply #5 on: April 21, 2010, 10:51:46 pm » I understand prof so when i would typing any equations i add$ between equations
For convert to picture right
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Fu-Kwun Hwang
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 « Embed this message Reply #6 on: April 22, 2010, 02:48:25 pm »

Yes!
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ahmedelshfie
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 « Embed this message Reply #7 on: April 22, 2010, 05:19:06 pm »

Yes prof
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