Shape of charged beam due to deviation in angle/velocity

Fu-Kwun Hwang

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1 Shape of charged beam due to deviation in angle/velocity

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on: February 13, 2010, 04:48:01 pm » posted from:Taipei,T\'ai-pei,Taiwan

A charge q with velocity v enter into a region with perpendular to magnetic field B, will move in a circular orbit.
The trajectory of the beam will spread out if the bean is deviated with a small angle $\theta$ (dca in the simulation) or with small deviation in velocity (dv)

The angle $\theta$ = dca * (random() -0.5); // where random() give random number between 0-1
The velocity v=V+ dv* (random() -0.5);

The trjjectory for all different possible paths are shown in the following simulation.

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macfamous

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2 Re: Shape of charged beam due to deviation in angle/velocity

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Reply #1 on: February 26, 2010, 01:04:55 am » posted from:Yogyakarta,Yogyakarta,Indonesia

may we change for the point random .. it means become positive ..


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Fu-Kwun Hwang

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3 Re: Shape of charged beam due to deviation in angle/velocity

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Reply #2 on: February 26, 2010, 10:29:26 am » posted from:Taipei,T\'ai-pei,Taiwan

The above simulation assume the beam enter into the magnetic field vertically (but there is a small angle deviation).
I think what you mean is that the beam might enter into the field with a angle.
The code has been updated, so that you can change the incident angle with slider c, or drag the red arrow to change it direction directly.

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Please feel free to post your ideas about how to use the simulation for better teaching and learning.
Post questions to be asked to help students to think, to explore.
Upload worksheets as attached files to share with more users.

Let's work together. We can help more users understand physics conceptually and enjoy the fun of learning physics!


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