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The most important medicine is tender love and care. ..."Mother Teresa(1910-1997, Roman Catholic Missionary, 1979 Nobel Peace Prize)"

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 Author Topic: Free Rolling and Circular Motion  (Read 95897 times) 0 Members and 1 Guest are viewing this topic. Click to toggle author information(expand message area).
Fu-Kwun Hwang
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 « Embed this message on: January 29, 2004, 01:13:25 pm » posted from:,,Satellite Provider

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This applet shows the positon,velocity and accelerationvectors
of a point on the rim of a body rolling without slippingon a stationary surface.

1. The term freely rolling means that there is no slipping (v=rw)
at the point of contact with the ground--no skidding (v>rw) and no spinning in place (w>v/r),where v,r and w are the linear speed, radius and
the angular speed of the rolling body.
2. The center of the wheel has a linear speed (with respect to ground)
equal to that of any point on its rim (with respect to center).
3. For circular motion (in the reference frame
moving with the velocity of the center of the rolling body) :
The acceleration a of a point always points in a direction
opposite the position vector r,
and the velocity vector V is perpendicular to both of them.
4. Observe the velocity vectors of a point on the rim
of the rolling body.
The white vector represents the velocity of the center
with resepect to ground and
the red vector represents the velocity of the point
with respect to the center.
The sum of these two vectors is the cyan vector
representing velocity of the point relative to ground.
5. The green curve shows the trajectory of a point on the rim.

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There are 4 translations,
Higher number at the end means more translation been done.
or
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Stam
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 « Embed this message Reply #1 on: January 15, 2009, 04:37:50 am »

Thnx very helpful but are there more like these. Where can i find?
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Fu-Kwun Hwang
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 « Embed this message Reply #2 on: January 15, 2009, 10:49:28 am » posted from:Taipei,T'ai-pei,Taiwan

There are several hundreds physics related simulation at this web site.
If there is some simulation you would like to have and you can not find it.
Write down in detail what you want, and I will try to help!
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thomasusa80
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 « Embed this message Reply #3 on: September 22, 2014, 12:49:40 pm » posted from:Faisalabad,Punjab,Pakistan

This applet shows the <font COLOR="#0000FF">positon</font>,<font COLOR="#0000FF">velocity</font> and <font COLOR="#0000FF">acceleration</font><font COLOR="#0000FF">vectors</font></font>
of a point on the rim of a body rolling without slipping</font>on a stationary surface.</font>
<center><applet code=freeRolling.class width=550 height=360 codebase="/java/FreeRolling/">
<param name="MSG1" value="Circular motion">
<param name="MSG2" value="Free Rolling">
<param name="Reset" value="Reset">
</applet></center><ol><font SIZE=+1>1. The term freely rolling means that there is no slipping (v=rw) </font><ol><font SIZE=+1>at the point of contact with the ground</font><font SIZE=+1>--no skidding (v>rw) and no spinning in place (w>v/r),</font><font SIZE=+1>where v,r and w are the linear speed, radius and</font><ol><font SIZE=+1>the angular speed of the rolling body.</font></ol></ol><font SIZE=+1>2. The center of the wheel has a linear speed (with respect to ground) </font><ol><font SIZE=+1>equal to that of any point on its rim (with respect to center).</font></ol><font SIZE=+1>3. For circular motion (in the reference frame</font><ol><ol><font SIZE=+1>moving with the velocity of the center of the rolling body) :</font></ol><font SIZE=+1>The acceleration a of a point always points in a direction</font><ol><font SIZE=+1>opposite the position vector r,</font></ol><font SIZE=+1>and the velocity vector V is perpendicular to both of them.</font></ol><font SIZE=+1>4. Observe the velocity vectors of a point on the rim</font><ol><ol><font SIZE=+1>of the rolling body.</font></ol><font SIZE=+1>The white vector represents the velocity of the center</font><ol><font SIZE=+1>with resepect to ground and </font></ol><font SIZE=+1>the red vector represents the velocity of the point</font><ol><font SIZE=+1>with respect to the center.</font></ol><font SIZE=+1>The sum of these two vectors is the cyan vector</font><ol><font SIZE=+1>representing velocity of the point relative to ground.</font></ol></ol><font SIZE=+1>5. The green curve shows the trajectory of a point on the rim.</font></ol>

There are a few hundreds physical science related reenactment at this site.

In the event that there is some reenactment you might want to have and you can not discover it.

Record in point of interest what you need, and I will attempt to offer assistance!

_Edwordstephen_
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diinxcom
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 « Embed this message Reply #4 on: December 14, 2014, 05:32:48 pm » posted from:,,Satellite Provider

-*-
please wait....
Maybe i will understand next time
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chengfu
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 « Embed this message Reply #5 on: October 26, 2015, 04:25:09 pm » posted from:Dhaka,Dhaka,Bangladesh

Video not worked, shows error
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Fu-Kwun Hwang
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 « Embed this message Reply #6 on: November 02, 2015, 10:55:12 am »

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The most important medicine is tender love and care. ..."Mother Teresa(1910-1997, Roman Catholic Missionary, 1979 Nobel Peace Prize)"
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