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Author Topic: Free Rolling and Circular Motion  (Read 74066 times)
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Fu-Kwun Hwang
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on: January 29, 2004, 01:13:25 pm » posted from:,,Satellite Provider

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This applet shows the positon,velocity and accelerationvectors
of a point on the rim of a body rolling without slippingon a stationary surface.




    1. The term freely rolling means that there is no slipping (v=rw)
      at the point of contact with the ground--no skidding (v>rw) and no spinning in place (w>v/r),where v,r and w are the linear speed, radius and
        the angular speed of the rolling body.
    2. The center of the wheel has a linear speed (with respect to ground)
      equal to that of any point on its rim (with respect to center).
    3. For circular motion (in the reference frame
        moving with the velocity of the center of the rolling body) :
      The acceleration a of a point always points in a direction
        opposite the position vector r,
      and the velocity vector V is perpendicular to both of them.
    4. Observe the velocity vectors of a point on the rim
        of the rolling body.
      The white vector represents the velocity of the center
        with resepect to ground and
      the red vector represents the velocity of the point
        with respect to the center.
      The sum of these two vectors is the cyan vector
        representing velocity of the point relative to ground.
    5. The green curve shows the trajectory of a point on the rim.


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There are 3 translations,
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or
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Stam
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Reply #1 on: January 15, 2009, 04:37:50 am »

Thnx very helpful but are there more like these. Where can i find?
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Fu-Kwun Hwang
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Reply #2 on: January 15, 2009, 10:49:28 am » posted from:Taipei,T'ai-pei,Taiwan

There are several hundreds physics related simulation at this web site.
If there is some simulation you would like to have and you can not find it.
Write down in detail what you want, and I will try to help!
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thomasusa80
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Reply #3 on: September 22, 2014, 12:49:40 pm » posted from:Faisalabad,Punjab,Pakistan

This applet shows the <font COLOR="#0000FF">positon</font>,<font COLOR="#0000FF">velocity</font> and <font COLOR="#0000FF">acceleration</font><font COLOR="#0000FF">vectors</font></font>
of a point on the rim of a body rolling without slipping</font>on a stationary surface.</font>
<center><applet code=freeRolling.class width=550 height=360 codebase="/java/FreeRolling/">
<param name="MSG1" value="Circular motion">
<param name="MSG2" value="Free Rolling">
<param name="Reset" value="Reset">
</applet></center><ol><font SIZE=+1>1. The term freely rolling means that there is no slipping (v=rw) </font><ol><font SIZE=+1>at the point of contact with the ground</font><font SIZE=+1>--no skidding (v>rw) and no spinning in place (w>v/r),</font><font SIZE=+1>where v,r and w are the linear speed, radius and</font><ol><font SIZE=+1>the angular speed of the rolling body.</font></ol></ol><font SIZE=+1>2. The center of the wheel has a linear speed (with respect to ground) </font><ol><font SIZE=+1>equal to that of any point on its rim (with respect to center).</font></ol><font SIZE=+1>3. For circular motion (in the reference frame</font><ol><ol><font SIZE=+1>moving with the velocity of the center of the rolling body) :</font></ol><font SIZE=+1>The acceleration a of a point always points in a direction</font><ol><font SIZE=+1>opposite the position vector r,</font></ol><font SIZE=+1>and the velocity vector V is perpendicular to both of them.</font></ol><font SIZE=+1>4. Observe the velocity vectors of a point on the rim</font><ol><ol><font SIZE=+1>of the rolling body.</font></ol><font SIZE=+1>The white vector represents the velocity of the center</font><ol><font SIZE=+1>with resepect to ground and </font></ol><font SIZE=+1>the red vector represents the velocity of the point</font><ol><font SIZE=+1>with respect to the center.</font></ol><font SIZE=+1>The sum of these two vectors is the cyan vector</font><ol><font SIZE=+1>representing velocity of the point relative to ground.</font></ol></ol><font SIZE=+1>5. The green curve shows the trajectory of a point on the rim.</font></ol>



There are a few hundreds physical science related reenactment at this site.

In the event that there is some reenactment you might want to have and you can not discover it.

Record in point of interest what you need, and I will attempt to offer assistance!



_Edwordstephen_
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diinxcom
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Reply #4 on: December 14, 2014, 05:32:48 pm » posted from:,,Satellite Provider

jasa pembuatan website / jual genset / jual genset

Huh  Huh  Huh please wait....
Maybe i will understand next time Smiley
« Last Edit: December 14, 2014, 06:45:10 pm by diinxcom » Logged
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