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Author Topic: Mass of liquid(beer) converted to volume  (Read 8286 times)
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Josh
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on: March 28, 2009, 04:43:58 am » posted from:Bangor,Michigan,United States

Lets say I mass a standard 12oz bottle of beer, just the liquid not the bottle. (specific gravity of this beer= 1.0113)  The scale reads 384.7g.  How do I convert this to a liquid volume.  I thougt I could convert the grams to ounces and then devide by specific gravity but it didn't look correct.  I got 13.42 fluid oz.  But I belive it to be closer to 12.2-12.4.  Any help would be much appriciated.  Huh
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lookang
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Reply #1 on: March 28, 2009, 09:13:10 am »

http://www.google.com/search?client=safari&rls=en-us&q=oz+to+gram&ie=UTF-8&oe=UTF-8
1 ounce = 28.3495231 grams

therefore 12 oz = 340.194 g

but your data is misleading as it is also 384.7g.
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Josh
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Reply #2 on: March 29, 2009, 11:55:48 pm »

This is true, but does not answer my question.  First off is an oz(mass) equal to an oz(fluid).  Second you did not take density into account which makes a significant difference.  My main goal is to be able to find the actual volume of the liquid by simply massing it, and doing a conversion.  Even though a bottle label states 12oz they are not usually that accurate.
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Fu-Kwun Hwang
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Reply #3 on: March 30, 2009, 08:50:03 am » posted from:Taipei,T\'ai-pei,Taiwan

I got the following information from wiki page http://en.wikipedia.org/wiki/Fluid_ounce
You might need to find out which oz is for your beer.

Fluid ounce

A fluid ounce (abbreviated fl oz, fl. oz. or oz. fl.) is a unit of volume in both the imperial and the US customary systems. It is common to refer to the unit simply as an ounce, especially in cases where no confusion with the unit of mass (also called an ounce) is likely to occur.


Imperial fluid ounce
  The imperial fluid ounce is 1⁄160 of an imperial gallon making it very nearly the volume occupied by one avoirdupois ounce of water[1].

  1 imperial fluid ounce    =    1/160   imperial gallons
    =    1/20   imperial pints
    =    1/5   imperial gills
    =    8   imperial fluid drams
    =    28.4130625   millilitres (exactly)[2] (cc)
    ≈    1.733871455   cubic inches
    ≈    0.960759940   U.S. fluid ounces

U.S. customary fluid ounce
  The U.S. customary fluid ounce is defined to be 1⁄128 of a U.S. gallon. This volume of cool, pure water weighs about 1.04 avoirdupois ounces (29.5 g).

  1 U.S. fluid ounce    =    1/128   U.S. gallon
    =    1/16   U.S. pints
    =    1/8   U.S. cup
    =    1/4   U.S. gills
    =    8   U.S. fluid drams
    =    1.80468754   cubic inches (exactly)[3]
    =    29.5735295625   millilitres (exactly)[4] (cc)
    ≈    1.040842731   imperial fluid ounces

U.S. food labeling fluid ounce
  U.S. regulation 21 CFR 101.9(b)(5)(viii) also defines a fluid ounce as exactly 30 millilitres, but this is for use in nutrition labeling only.[5] This is not meant to concur with the customary US definition exactly but is a common source of confusion.[citation needed]

  30 millilitres    ≈    1.055852392   imperial fluid ounces[2]
    ≈    1.014420681   U.S. customary fluid ounces[3][4]
    ≈    1.830712323   cubic inches[4]

Other useful conversions

Given the definitions above, the number of US fluid ounces in one liter is:

  1/29.5735295625 × 1000 = 33.8140

There are thus about 34 customary US fluid ounces in one liter.

Similarly, there are exactly 33 1/3 US food-labeling fluid ounces in a liter.
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Josh
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Reply #4 on: March 30, 2009, 11:10:58 pm »

This is helpful, but I still don't know how to convert directly between grams and ml.  Also what equation do I need to deel with the different densities of beers.  Some beers will have a density of 1.008 and others will have a density of 1.020.  This will change my results quite a bit. 
thank you for all of your help
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Fu-Kwun Hwang
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Reply #5 on: March 30, 2009, 11:36:08 pm » posted from:Taipei,T\'ai-pei,Taiwan

For 384.7 g and density 1.0113:
The volume is 384.7g/1.0113=380.4 cm3 or 380.4 cc

for U.S. customary fluid ounce:
 1 oz=29.5735295625 cc
so 380.4 cc=12.86 oz

But I do not know which oz unit for your case.
You need to know the exact value for the density, otherwise, you can estimate the range.
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