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Author Topic: Electricity Generator With Buoyant Magnet Assembly  (Read 24071 times)
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xirja
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on: March 06, 2009, 06:03:37 am »

Hi,

I was happy to see both the Buoyant Force and the Induction simulations.  Can you combine the two in a way such as:



whereby the tops of two of the above figures are near the center of rotation of a spinning cylinder, so that G can be modulated?


Dimitri Vorkapich

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Fu-Kwun Hwang
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Reply #1 on: March 06, 2009, 08:27:55 am »

I do not understand how the above device works. PLease write down physics description about how it works.
I need to fully understand it to be able to create simulation.
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xirja
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Reply #2 on: March 06, 2009, 08:32:50 pm »

The object is to relate angular velocity to inductance, buoyancy, and gravity
with respect to a buoyant permanent magnet in order to produce electricity.

A small permanent magnet embedded in a low density material ( the capsule ), rises
through a high density non viscous fluid in tube section 1.  The buoyant capsule leaps
out of the fluid and is guided by inertial forces around the top ( frictionless ) and then
falls down tube section 2.

Both tube sections have coils for inducing a current.  At the bottom there is an electric
motor rotating the section with the red spaces which transfers the capsule from the higher
section 2 to the lower section 1.  The red space is where the capsule moves through.  The
blue space is where the fluid moves through and is fixed  ( There is an error in the graphic
- the blue lines indicating the fluid channel should be in front of the grey lines).  The black
bar is the displacement bar.

Then to have two of the figures embedded in a cylinder and aligned about an axis to
allow for G to be increased:

..........|..........
....__...|...__....
...o__) | (__o...
..........|..........

<------G------>

Maybe for general demonstration it would be better to leave out the exchange section and
have the capsule manually inserted for a one time spin through?



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« Last Edit: March 06, 2009, 08:48:18 pm by xirja » Logged
Fu-Kwun Hwang
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Reply #3 on: March 06, 2009, 08:46:04 pm » posted from:Taipei,T\'ai-pei,Taiwan

1. I do not understand why you called it an electricity generator ? Where is the input energy comimg from?
2. If the magnet at the left side moving up is due to Buoyant, why it moving down at the right side?
 If the system is symmetry, the physics should be the same.
3. Is there any non viscous fluid in real life? Have you found one? Is this a "thought experiment"/device?
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xirja
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Reply #4 on: March 06, 2009, 08:57:19 pm »

1.  The motion of the permanent magnet through a conductive coil, DC generation.

2.  The right side has no fluid, it is air.

3.  I am not sure, it is probably an ideal.  No.  The lower the viscosity the better.
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Reply #5 on: March 06, 2009, 09:18:54 pm » posted from:Taipei,T\'ai-pei,Taiwan

O.K. The right side is air.
How can the magnet leave the fluid and moving into air ?
And how can magnet enter the fluid again? The pressure at the bottom of the fluid is higher than the air.
You need to provide energy!

It seems to be another device which violate the conservation of energy.
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xirja
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Reply #6 on: March 06, 2009, 09:55:27 pm »

As in your demonstration:

http://www.phy.ntnu.edu.tw/ntnujava/index.php?topic=266.0

If the density of the block is .25 and all the other initial conditions are the same,
the block leaps into the air.  The lower the block density, the higher into the
air the block goes.

The rotating exchange section divides the two tubes so that the pressure at the
bottom of the water filled section 1 never interacts with the air filled section 2
directly.

In Figure 3c:



You can see that when the section has rotated to this point the red sections are not
connected to either fluid filled section 1 or air filled section 2.






« Last Edit: March 06, 2009, 10:17:18 pm by xirja » Logged
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Reply #7 on: March 06, 2009, 10:14:17 pm » posted from:Taipei,T\'ai-pei,Taiwan

1. It is a simulation for teaching purpose and it is assume there is no viscoity(ideal fluid).
2. No matter what you did. The magnet need to move from air (lower pressure region) to bottom of fluid (higher pressure region). Otherwise, it is not a continue workable loop.
You need to do WORK to move magnet from air back into fluid again.
The WORK you need at least should equal the energy you gain when it move up.

From my point of view: It is not a workable device and it violate the physics principle I have learned. 
So I would not be able to create a simulation for you. Sorry!
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xirja
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Reply #8 on: March 06, 2009, 10:36:58 pm »

But as N loops can vary ( the length of the sections ), and G can vary ( the rate
of rotation ), there is a point at which the output is greater than that used to turn
the section at the bottom.

Anyhow I do appreciate you considering the item.

So, I think it is wonderful that you have these demonstrations.  To be joined
together in useful form at a later date!

http://www.phy.ntnu.edu.tw/ntnujava/index.php?topic=266.0  Buoyancy

http://www.phy.ntnu.edu.tw/ntnujava/index.php?topic=687.0  Induction

http://www.phy.ntnu.edu.tw/ntnujava/index.php?topic=192.0  Centripetal Force


Thank you,


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xirja
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Reply #9 on: March 17, 2009, 01:37:56 am »

Also forgot to mention the possibility of using Mercury (Quicksilver).  With a viscosity near to water
and a density ~13.6 times as great as water, wouldn't a magnet embedded in a styrofoam capsule fly?


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xirja
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Reply #10 on: April 12, 2009, 08:47:14 pm »

Just finished conceptual animations if it is of any interest.




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