Title: Circulation Motion and Centripetal Force Post by: FuKwun Hwang on January 29, 2004, 05:00:44 pm When an object is in circular motion, it need centripetal force.
The red ball is initially orbiting in a circle of radius r with velocity v. A black ball is tied to the other end of the green cord. If it is in equilibrium,
provides the centripetal force Fc needed. Fc = m v^{2}/r = m w^{2} r ( v=w*r) Fg = Fc i.e. Mg = m w^{2} r 1. Click the black ball and drag it up and down to change the radius r.
Click with right mouse button: The mass of black is the same. The system starts oscillation. 2. The torque acting on the red ball is zero since F is parallel to r.
w = constant When the radius r is changing, centripetal force Fc = (rmv)^{2}/(mr^{3})= L^{2}/(mr^{3}) changes ,too. 3. Click the right mouse button to pause, click it again to resume. When the animation is suspended, Click at the red ball and drag the mouse button to change its tangential vector, and the mass of black ball will also change to keep in the same radius. If you click the right mouse button and drag it up/down/left/right, you can rotate the coordinate system. 4. Click trace check box to trace the trajectory, Press Clean Button to clear the trace. 5. Parameters : A short white arrow represents the velocity vector v = r w. where w : angular frequency , r : radius Mg/m: Mg gravitation force for black ball, m is the mass of red ball. Title: topic6 Post by: on January 30, 2004, 11:49:08 am Subject: Physics applets comments
Date: Wed, 28 Apr 1999 12:56 0500 (CDT) From: Michael Blackstock <michael.blackstock@wcom.com> To: hwang@phy03.phy.ntnu.edu.tw FuKwun Hwang, Hello, I am an amateur American physics enthusiasts. Your physics page has caught my attention and I would like to let you know they are wonderful. Under Dynamics on 6. Circulation motion and Centripetal force, I would like to know if it possible to change the velocity of the circular motion and change both the weights on either end of the string without changing it's radius? Thank you, Michael Blackstock  Subject: Re: Physics applets comments Date: Fri, 30 Apr 1999 10:46 0500 (CDT) From: Michael Blackstock <michael.blackstock@wcom.com> To: hwang@phy03.phy.ntnu.edu.tw FuKwun Hwang, Thank you very much for the adjustments you made to the following request I sent you! Sincerely, Title: topic6 Post by: on January 30, 2004, 12:51:04 pm Subject: http://www.phy.ntnu.edu.tw/java/circularMotion/circular3D_e.html
Date: Sat, 09 Oct 1999 12:15:20 0400 From: A Friend <a.friend@oln.com> To: hwang@phy03.phy.ntnu.edu.tw nice page. thank you. Title: Re: Circulation Motion and Centripetal Force Post by: a_a_quintero on October 03, 2007, 10:48:16 am awesome webpage. thank you very much for these applets. they are a great help in understanding the concepts. once again, thank you very much
alex Title: Re: Circulation Motion and Centripetal Force Post by: physicsbysabbs on December 09, 2008, 01:36:56 am Hi, I think this applet is great and I want to use it for my high school physics class.
My goal is to have my students investigate the relationships involved in circular motion. I want them to understand the relationship between the following  the centripetal force as a function of mass (with velocity and radius remaining constant)  the centripetal force as a function of velocity (with mass and radius remaining constant)  the centripetal force as a function of radius (with velocity and mass remaining constant) With the applet, I have successfully been able to accomplish the third, but I can not find a way to manipulate for the other two. Is there a way that can be done? Thank you, Nicole Title: Re: Circulation Motion and Centripetal Force Post by: FuKwun Hwang on December 09, 2008, 11:27:34 pm The condition for the system in equilibrium is: Mg = m w^{2}r =m v^{2}/r .
The mass m is the same in the above simulation. First right click to pause the simulation. LEFT Click at the black dot (mass M) and drag it up and down, you will change r and M at the same time. (Keep the total length of the string the same). There is no way to keep the system in equilibrium if you change radius r ,and keep velocity v and mass M remaining constant. If you LEFT Click at the red dot (mass m) and drag the mouse, you will change velocity v and mass M at the same time. (keep r the same). For your cases:  the centripetal force as a function of mass M(with velocity v and radius r remaining constant) Then m is proportional to M.  the centripetal force as a function of velocity v(with mass M and radius r remaining constant) Then m is proportional to v^{2}  the centripetal force as a function of radius r (with velocity v and mass M remaining constant) Then m is proportional to 1/r Do you really want to simulate the above situations? Title: Re: Circulation Motion and Centripetal Force Post by: lookang on December 12, 2008, 01:22:48 am Hi, I think this applet is great and I want to use it for my high school physics class. My goal is to have my students investigate the relationships involved in circular motion. I want them to understand the relationship between the following  the centripetal force as a function of mass (with velocity and radius remaining constant)  the centripetal force as a function of velocity (with mass and radius remaining constant)  the centripetal force as a function of radius (with velocity and mass remaining constant) With the applet, I have successfully been able to accomplish the third, but I can not find a way to manipulate for the other two. Is there a way that can be done? Thank you, Nicole Did this help?? http://www.phy.ntnu.edu.tw/ntnujava/index.php?topic=817.msg3090#msg3090 follow the link and download the *.jar file for the applet Title: Re: Circulation Motion and Centripetal Force Post by: FuKwun Hwang on June 26, 2009, 05:27:22 pm Here is an EJS version of the same applet.
