# NTNUJAVA Virtual Physics LaboratoryEnjoy the fun of physics with simulations! Backup site http://enjoy.phy.ntnu.edu.tw/ntnujava/

## Easy Java Simulations (2001- ) => Collaborative Community of EJS => Topic started by: lookang on August 29, 2012, 04:23:11 pm

 Title: Ejs Open Source Heat capacity and Specific heat capacity Java Applet Post by: lookang on August 29, 2012, 04:23:11 pm Ejs Open Source Heat capacity and Specific heat capacity Java Applet by lookang, customized based on an earlier model http://www.compadre.org/osp/items/detail.cfm?ID=10071 by Wolfgang Christian.Aims1.   To investigate the relationship between the heat capacity of an object and the heat transferred per unit temperature change of the object.2.   To infer the specific heat capacity of a substance from the heat capacity of an object of the same substance.Syllabus Learning OutcomeThis lesson exemplar addresses the following learning outcome:-   define the terms heat capacity and specific heat capacity-   recall and apply the relationship             Thermal energy = mass X specific heat capacity X change in temperatureAssumption in the modelheat lost by the solid cylinder to the water is completely gain by the water, in other words, the container containing the water and solid cylinder is a perfect insulator. Definition Equation 1The heat capacity, C, of a body is defined as the amount of heat (or thermal energy) required to raise the temperature of a body by 1 oC (or 1 K).therefore, heat capacity, C (units: J oC-1) =       heat transferred (in J) / temperature change (in  oC)    Definition Equation 2The specific heat capacity, c, of a substance is defined as the amount of heat (or thermal energy) required to raise the temperature of a unit mass of the substance by 1 oC (or 1 K).therefore specific heat capacity,  c    (in J oC-1kg-1 )  =       heat transferred (in J)  / temperature change (in oC) x mass of object (in kg)                               Title: Re: Ejs Open Source Heat capacity and Specific heat capacity Java Applet Post by: lookang on August 29, 2012, 04:32:56 pm changes made:design the water properties and rate of heat flow to depend on water instead of the older surroundingmade water mass and initial temperature variablesadded hints and answers Qsolid and Qwater, notice Qsolid + Qwater = 0, assuming no heat Q loss to surroundingdata here https://docs.google.com/spreadsheet/ccc?key=0AjIvSg-TzZrZdFpVOXRTMlZrb2J1UEd5VThxZlJrQlEm   C   Ti   Tf   Q = mc(tf-Ti)   Tf-Ti0.1   385   20   52.6   1,255   32.60.1   385   20   61.9   1,613   41.90.1   385   20   71.2   1,971   51.20.1   385   20   80.6   2,333   60.60.1   385   20   89.9   2,691   69.9work in progressenjoy!