# NTNUJAVA Virtual Physics LaboratoryEnjoy the fun of physics with simulations! Backup site http://enjoy.phy.ntnu.edu.tw/ntnujava/

## Information about this web site => Question related to Physics or physics related simulation => Topic started by: Stuckonphysics on October 05, 2011, 11:31:27 pm

 Title: I'm soooooo lost on this one problem my teacher gave me; Forces on an Incline Post by: Stuckonphysics on October 05, 2011, 11:31:27 pm I really need to know HOW to do this problem... and why... He gave us an incline that is 30˚ with a box on top of the incline. When the Ms =0.5 and Mk = 0.3.What happens?-Does it move?-If so, what's the acceleration?So far :I have drawn a force diagram that shows f to the left of the box, mg down from the box, and N (normal force) up from the box... Then,Fxnet=max and fynet=maySo, -fk=max and N-mg=mayis any of this right?... and if not... can someone PLEASE HELP. Title: Re: I'm soooooo lost on this one problem my teacher gave me; Forces on an Incline Post by: Fu-Kwun Hwang on October 06, 2011, 03:19:11 pm What are the meaning of Ms and Mk? Are they coefficient for static friction and kinetic friction?You can calculate the component of gravitation force (mg) along the incline direction ($m\,g\,\sin\theta$)and normal direction (m g ??? this is for your!) ,and find out the friction force.Try to write down whatever you know and we will try to help you!