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Easy Java Simulations (2001- ) => Electromagnetism => Topic started by: Fu-Kwun Hwang on February 15, 2011, 11:20:41 pm



Title: Relation between displacement current and electric field with R-C circuit
Post by: Fu-Kwun Hwang on February 15, 2011, 11:20:41 pm
The electric displacement field is defined as:
$ \boldsymbol{D} = \varepsilon_0 \boldsymbol{E} + \boldsymbol{P}\ =\varepsilon \boldsymbol{E}$.

where:
    ε0 is the permittivity of free space
    E is the electric field intensity
    P is the polarization of the medium

The folliwing use RC-circuit to show relation between displacement current and electric field.

To make it easier, the value of ε0 is assigned as 0.5

Un-check the off check box to connect the DC voltage source to the RC circuit (ON).
 k is the dielectric constant $\varepsilon/\varepsilon_0$.
You can adjust voltage source Vs, resistance R, capacitance C.