NTNUJAVA Virtual Physics Laboratory (Java Simulaions in Physics)
July 24, 2008, 04:48:38 PM *
Welcome, Guest. Please login or register.
Did you miss your activation email?

Login with username, password and session length
News: Switch to this new system on 2007/02/14. (previous system2001-2007, 1996-2001) ,Chinese forum more simulations and resources in Chinese.
 
   Home   Help Search Login Register  
NTNUJAVA Virtual Physics Laboratory (Java Simulaions in Physics) > JDK1.0.2 simulations (1996-2001) > Electromagnetics > Charged particle motion in E/M Field
Pages: [1]
« previous next »
  Print  
Author Topic: Charged particle motion in E/M Field  (Read 102903 times)
0 Members and 1 Guest are viewing this topic.
Fu-Kwun Hwang
Administrator
Hero Member
*****
Posts: 1029



WWW
« on: January 29, 2004, 09:54:42 PM »
Registed user can get files related to this applet for offline access.
If java program did not show up, please download and install latest Java RUN TIME
There are 2 translations,
or




This java applet tries to show :
    The motion of a charged particle in a uniform and constant electric/magnetic field
  1. Particle starts at the origin of the coordinate system

  2. Blue arrow starts from the origin shows the magnetic field (always in the Y direction)

  3. Red arrow starts from the origin shows the electric field.

    4. LEFT Click near the tip of the arrow, and drag the mouse to change the E field (Both direction and magnitude),
    The black arrow on X-Z plane shows the drift velocity Vd

  4. You can also key in values in the textFields to change E / B fields.

    5. Do not forget to hit the RETURN key after enter the value into the textfield.

  5. Change the coordinate system:

    1. Translation : LEFT Click near the origin, and drag the mouse

    2. Rotation: RIGHT Click within the window and drag the mouse

  6. Change the initial Velocity V:

    7. Left click the mouse button within the window and drag the mouse

  7. The above changes depend on where you press the mouse button.

    8. (X-Y, Y-Z or Z-X plane, watch the color of the axis)

  • Press start button to start the animation

    1. The position, initial velocity and the period of the motion are shown at the top left region.

    2. During the animation

      1. If the trajectory is not on the X-Z plane :

        1. Its color is GREEN

        2. The black curve shows projection of the trajectory on the X-Z plane.

      2. RED arrow reprenents velocity of the charge

      3. BLUE arrow represents the force acting on the charge.

      4. Press the LEFT mouse button will suspend the animation, press it again to resume.

      5. Click the checkbox on the right to save all the traces

      6. Drag the RIGHT mouse button to change the viewing angle.

        1. Animation resumes when you release the mouse button -- with the same initial condition

        2. If the trace is saved, you can view the trace from various angle.

    3. Press Reset button to reset the condition



    Physics Law:
      The Lorentz frce acting on a point charge q is given by F = m a = q ( E + V X B )
    1. If E=0. ¡GF = q V X B is perpendicular to both V and B
      (example 1)

      1. If initial velocity V is perpendicular to magnetic field B, the change will move in a circular orbit with

        2. P = m V = q R X B

        (R is the radius of the circular motion)

      2. The period of the motion is not depend on the velocity

      the angular frequency (also known as cyclotron frequency)

        w = q B / m

      1. Try with larger q/m value (let q/m=0.1) ! charge moves along B field

    2. If EXB exists, the charge will drift in that direction with drift velocity Vdrift = EXB/|B|2.

      3. called "E cross B drift"
      ( example 2)
       
      ( example 3)
       
      Try it with a larger q/m value ( let q/m=0.1 => smaller radius R)!


      Electrostatic Field
      1. The work done by the field will increase the kinetci energy of the change particle K = q E¡ER (R is the displacement vector¡^
      2. Particles with different velocities will spread out in E field
      Magnetostatic Field
      1. Magnetostatic field can not change the kinetic energy of the particle ( only change the direction of its velocity, F is always perpendicular to its velocity V¡^
      2. The cyclotron frequency does not depend on the speed of the particle or the radius of the orbit.
        3. Particles with different velocities will not spread out in a uniform magnetostatic field.


    Registed user can get files related to this applet for offline access.
    If java program did not show up, please download and install latest Java RUN TIME
    There are 2 translations,
    or
    Logged
    Guest
    « Reply #1 on: January 30, 2004, 12:52:38 PM »
    Subject: applet
    Date: Fri, 15 Oct 1999 14:09:41 -0400
    From: Daniel Lemire <Daniel.Lemire@Videotron.ca>
    To: hwang@phy03.phy.ntnu.edu.tw
    Good day,

    I checked your E/M applet today. Maybe you can help me out...

    When I set both E and M fields to zero, I would expect the particule to
    move at a constant speed in a constant direction (or possibly stay still).

    Yet, no matter what I do, it doesn't seem to work.

    I am just trying to show to a friend that a charged particule standing
    still in a magnetic field won't feel a thing... if there is not E field.
    Your applet would be perfect... but it doesn't give the desired result.
     

    Daniel Lemire


    --------------------------------------------------------------------------------

    Subject: Re: applet
    Date: Fri, 15 Oct 1999 22:11:30 -0400
    From: Daniel Lemire <Daniel.Lemire@Videotron.ca>
    To: Fu-Kwun Hwang <hwang@phy03.phy.ntnu.edu.tw>
    Thanks for your quick reply!
    Logged
    Guest
    « Reply #2 on: April 03, 2004, 02:10:44 PM »
    Quote from: "Anonymous"
    Subject: applet
    Date: Fri, 15 Oct 1999 14:09:41 -0400
    From: Daniel Lemire <Daniel.Lemire@Videotron.ca>
    To: hwang@phy03.phy.ntnu.edu.tw
    Good day,

    I checked your E/M applet today. Maybe you can help me out...

    When I set both E and M fields to zero, I would expect the particule to
    move at a constant speed in a constant direction (or possibly stay still).

    Yet, no matter what I do, it doesn't seem to work.

    I am just trying to show to a friend that a charged particule standing
    still in a magnetic field won't feel a thing... if there is not E field.
    Your applet would be perfect... but it doesn't give the desired result.
     

    Daniel Lemire


    --------------------------------------------------------------------------------

    Subject: Re: applet
    Date: Fri, 15 Oct 1999 22:11:30 -0400
    From: Daniel Lemire <Daniel.Lemire@Videotron.ca>
    To: Fu-Kwun Hwang <hwang@phy03.phy.ntnu.edu.tw>
    Thanks for your quick reply!
    Logged
    parrenas18
    Newbie
    *
    Posts: 1
    « Reply #3 on: March 17, 2006, 03:16:15 PM »
    Can get your codes in the particle charge in motion.... Because i have a science project about the said topic and i need to make a simulator... I need a code reference to make that project plsssssssss!!!!!!!!!!!!!!!!1
    Logged
    delores.knipp
    Newbie
    *
    Posts: 1
    « Reply #4 on: February 22, 2007, 01:33:21 AM »
    Is it possible to download the files rather than having them e-mailed?  My firewall is stripping off the attachments to your e-mails.

    Delores Knipp
    Logged
    hwang
    Administrator
    Newbie
    *****
    Posts: 6
    « Reply #5 on: February 22, 2007, 04:22:44 PM »
    Please change you firewall setting or email acoount setting!
    Logged
    guybrush
    Newbie
    *
    Posts: 1
    « Reply #6 on: April 25, 2007, 03:43:19 AM »
    Hello,
    I observed that in the java applet "Charged particle motion in E/M Field" when there exits both magnetic(y-axis) and electric field (x-axis), and initial velocity has only i (x) component, charge drifts in Z direction. B causes charge to make rotational motion and E causes it to drift, this is what I assume. According to my assumption, charge should drift in the direction of electric field, in x direction. 
    What is the reason of moving in Z direction? I would like to learn the nature of the motion. My second question is when we solve equation m a = q ( E + V X B ), we get (for conditons above) qE = m dVx/dt which means acceleration is constant in X axis; is it possible for a drifting motion to have constant acceleration?
    Thanks for your help
    Hasan Serce
    Logged
    Fu-Kwun Hwang
    Administrator
    Hero Member
    *****
    Posts: 1029



    WWW
    « Reply #7 on: April 25, 2007, 01:02:21 PM »
    If the velocity of a charge particle is perpendicular to the B field,
    The force q vXB will cause a particle to move in a circle with constant velocity.
    From qvB=m v2/r so r=mv/(qB)
    The E field will cause a particle to accelerate along the field direction.

    Now, we have a charge particle in E and B field.
    The circular motion radius r=mv/(qB), which is dependent on the velocity of the particle.
    Because the velocity is changing due to E field, so the circular radius r also is changing,too.
    The changing in radius cause the particle to drift in the EXB direction, so called EXB drift (E cross B drift).
    Logged
    prendergast.david
    Newbie
    *
    Posts: 2
    « Reply #8 on: November 03, 2007, 02:32:07 AM »
    any chance i can get the source code for this as it would really help with a project im doing. thanks
    Logged
    Fu-Kwun Hwang
    Administrator
    Hero Member
    *****
    Posts: 1029



    WWW
    « Reply #9 on: November 03, 2007, 04:35:08 PM »
    You should have received the source code now.
    Logged
    prendergast.david
    Newbie
    *
    Posts: 2
    « Reply #10 on: November 04, 2007, 05:06:15 AM »
    Thanks very much. got it and helped loads. thanks!
    Logged
    blackjackchik
    Newbie
    *
    Posts: 1
    « Reply #11 on: May 12, 2008, 02:35:37 PM »
    Please send me source code too.
    Logged
    Pages: [1]
      Print  
    « previous next »
     
    Jump to:  

    Powered by MySQL Powered by PHP Powered by SMF 1.1.5 | SMF © 2006-2008, Simple Machines LLC Valid XHTML 1.0! Valid CSS!